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3 years ago

This is an organism which feeds on but usually does not kill a larger organism

Physics

2 answers:

SpyIntel [72]3 years ago

4 0

Epiparasite is an organism which feeds on but usually does not kill a larger organism.

Explanation:

The relationship between an epiparasite and host is defined by the phrase where the epiparasite feeds on the host without killing the host. The host is the larger organism which serves as the platform for food.

Parasite is the smaller organism which preys over the host for food. There are different parasitism, of which when the parasite withdraw affordable amount of food without killing the host is called as the Epiparasitism or the Hyperparasitism.

Arte-miy333 [17]3 years ago

3 0

An epiparasite is a parasite that parasitizes another organism that is also a parasite. Epiparasites are also called hyperparasites or secondary parasites. They feed on another organism, but they do not kill the organism they feed on.

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Choose the sources of gamma rays. Check all that apply.

harina [27]

Answer:

a. Stars all warm objects

c. Some unstable atomic nuclei

Explanation:

Gamma rays are photons of very high energy (beyond 100keV) enough to remove an electron from its orbit.

They have a very short wavelength, less than 5 meters from the peak, and can be produced by nuclear decay, especially in the breasts of massive stars at the end of life.

They were discovered by the French chemist Paul Villard (1860 to 1934).

While X-rays are produced by electronic transitions in general caused by the collision of an electron with an atom at high speed, gamma rays are produced by nuclear transitions.

Gamma rays produce damage similar to those caused by X-rays or ultraviolet rays (burns, cancer and genetic mutations).

The sources of gamma rays that we observe in the universe come from massive stars (hypernovas) or some warm objects on the space that end their lives by a gravitational collapse that leads to the formation of a neutron star or a black hole, as well as unstable radioactive nuclei that emit radiation gamma to reach its steady state.

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4 years ago

during a space shuttle launch about 830,000 kg of fuel is burned in 8 min. the fuel provides the shuttle with a constant thrust,

kirill115 [55]

The shuttles acceleration in the creases as the fuel is burned because the acceleration of the obect as produced by net force is directly proportional to the magnitude of the net force.

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3 years ago

A satellite orbiting above the earth needs no power source to keep orbiting the earth.

abruzzese [7]

Answer:

True

Explanation:

The earths gravitational pull keeps it consistent with its orbit.

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3 years ago

Read 2 more answers

A boy reaches out of a window and tosses a ball straight up with a speed of 10 m/s. The ball is 20 m above the ground as he rele

HACTEHA [7]

Answer:

25 m

9.9 m/s

22 m/s

Explanation:

m = Mass of ball

v = Velocity

g = Acceleration due to gravity = 9.81 m/s²

Applying conservation of energy

$mgh=\dfrac{1}{2}mv^2\\\Rightarrow h=\dfrac{v^2}{g}\\\Rightarrow h=\dfrac{10^2}{2\times 9.81}\\\Rightarrow h=5.09683\ m$

The height above the ground is 5.09683+20 = 25.09683 m = 25 m

$mgh=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}\\\Rightarrow v=\sqrt{2\times 9.81\times 5}\\\Rightarrow v=9.9\ m/s$

The ball's speed as it passes the window on its way down is 9.9 m/s

$mgh=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}\\\Rightarrow v=\sqrt{2\times 9.81\times 25}\\\Rightarrow v=22.14723\ m/s$

The speed of impact on the ground is 22 m/s

7 0

3 years ago

A mass of 5kg starts from rest and pulls down vertically on a string wound around a disk-shaped, massive pulley. The mass of the

bekas [8.4K]

Answer:

1.98 m/s

Explanation:

To solve this, we would be using the law of conservation of energy, i.e total initial energy is equal to total final energy.

E(i) = E(f)

mgh = ½Iw² + ½mv²

Recall, v = wr, thus, w = v/r

Also, I = ½mr²

I = 0.5 * 5 * 2²

I = 10 kgm²

Remember,

mgh = ½Iw² + ½mv²

Substituting w for v/r, we have

mgh = ½I(v/r)² + ½mv²

Now, putting the values in the equation, we have

5 * 9.8 * 0.3 = ½ * 10 * (v/2)² + ½ * 5 * v²

14.7 = 1.25 v² + 2.5 v²

14.7 = 3.75 v²

v² = 14.7/3.75

v² = 3.92

v = √3.92

v = 1.98 m/s

Thus, the speed is 1.98 m/s

5 0

3 years ago