Answer:
49.35 mL
Explanation:
Given: 56.2 mL of gas
To find: volume that 56.2 mL of gas at 820 mm of Hg would occupy at 720 mm of Hg
Solution:
At 820 mm of Hg, volume of gas is 56.2 mL
At 1 mm of Hg, volume of gas is 
At 720 mm of Hg, volume of gas is 
Answer:
<u>136.67 g of Na3PO4 i</u>s required to create 100 gram of NaOH.
Explanation:
The balanced equation:
1 mole Na3PO4 = 164 g/mole (Molar mass)
1 mole NaOH = 40 g/mole (Molar mass)
Now,
1 mole of Na3PO4 produce = 3 mole of NaOH
164 g/mol of Na3PO4 produce = 3(40) g/mol of NaOH
or
120 g/mol of NaOH is produced from = 164 g/mol of Na3PO4
1 g/mol of NaOH is produced from =
100 grams of NaOH is produced from =
gram of Na3PO4
calculate,
= 136.67 g
Answer:The best phrase which supports the eruption would be high-viscosity magma lava broken into fragments.
Explanation:
example is copper iron...........
The half-life in months of a radioactive element that reduce to 5.00% of its initial mass in 500.0 years is approximately 1389 months
To solve this question, we'll begin by calculating the number of half-lives that has elapsed. This can be obtained as follow:
Amount remaining (N) = 5%
Original amount (N₀) = 100%
<h3>Number of half-lives (n) =?</h3>
N₀ × 2ⁿ = N
5 × 2ⁿ = 100
2ⁿ = 100/5
2ⁿ = 20
Take the log of both side
Log 2ⁿ = log 20
nlog 2 = log 20
Divide both side by log 2
n = log 20 / log 2
<h3>n = 4.32</h3>
Thus, 4.32 half-lives gas elapsed.
Finally, we shall determine the half-life of the element. This can be obtained as follow.
Number of half-lives (n) = 4.32
Time (t) = 500 years
<h3>Half-life (t½) =? </h3>
t½ = t / n
t½ = 500 / 4.32
t½ = 115.74 years
Multiply by 12 to express in months
t½ = 115.74 × 12
<h3>t½ ≈ 1389 months </h3>
Therefore, the half-life of the radioactive element in months is approximately 1389 months
Learn more: brainly.com/question/24868345
