The Structure of Glycine is attached below and each central atom is encircled with different colors.
Molecular Shape around Nitrogen Atom (Orange):
As shown, Nitrogen is making three single bonds with two hydrogen atoms and one carbon atom hence, it has three bonded pair electrons and a single lone pair of electron. Therefore, according to VSEPR theory it has a tetrahedral electronic geometry but due to repulsion created by lone pair of electrons its molecular geometry becomes Trigonal Pyramidal.
Molecular Shape around Carbon Atom (Green):
As shown, Carbon is making four single bonds with two hydrogen atoms and one nitrogen atom one with carbon atom of carbonyl group hence, it has four bonded pair electrons. Therefore, according to VSEPR theory it has Tetrahedral geometry.
Molecular Shape around Carbon Atom (Blue):
As shown, Carbon is making two single bonds with oxygen and carbon atoms and a double bond with oxygen. Hence, it has a Trigonal Planar geometry.
Molecular Shape around Oxygen Atom (Red):
As shown, Oxygen is making two single bonds with one carbon atoms and one hydrogen atom hence, it has two bonded pair electrons and two lone pair of electrons. Therefore, according to VSEPR theory it has a tetrahedral electronic geometry but due to repulsion created by lone pair of electrons its molecular geometry becomes Bent.
Answer:
Acceleration
Explanation:
The rate at which velocity changes with time is called Acceleration is a measure of how quickly the velocity is changing. If velocity does not change, there is no acceleration.
Answer:
Because energy is conserved, the kinetic energy of a block at the bottom of a frictionless
ramp is equal to the gravitational potential energy of the block at the top of the ramp. This
value is proportional to the square of the block’s velocity at the bottom of the ramp.
Therefore, the block’s final velocity depends on the height of the ramp but not the steepness
of the ramp
Explanation:
Answer:
<h2>Density = 0.00026 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
<h3>
</h3>
From the question
mass of air = 1.2 g
volume = 4,555 mL
Substitute the values into the above formula and solve for the density
That's
<h3>
</h3>
= 0.0002634
We have the final answer as
<h3>Density = 0.00026 g/mL</h3>
Hope this helps you
Answer:
a) K = 5.3175
b) ΔG = 3.2694
Explanation:
a) ΔG° = - RT Ln K
∴ T = 25°C ≅ 298 K
∴ R = 8.314 E-3 KJ/K.mol
∴ ΔG° = - 4.140 KJ/mol
⇒ Ln K = - ( ΔG° ) / RT
⇒ Ln K = - ( -4.140 KJ/mol ) / (( 8.314 E-3 KJ/K.mol )( 298 K ))
⇒ Ln K = 1.671
⇒ K = 5.3175
b) A → B
∴ T = 37°C = 310 K
∴ [A] = 1.6 M
∴ [B] = 0.45 M
∴ K = [B] / [A]
⇒ K = (0.45 M)/(1.6 M)
⇒ K = 0.28125
⇒ Ln K = - 1.2685
∴ ΔG = - RT Ln K
⇒ ΔG = - ( 8.314 E-3 KJ/K.mol )( 310 K )( - 1.2685 )
⇒ ΔG = 3.2694
