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FromTheMoon [43]
3 years ago
15

If there's a jar that contains helium gas . What would happen if the lid of the jar was removed ?

Chemistry
1 answer:
Sergio039 [100]3 years ago
6 0
The helium would float away because it's lighter than air.
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Please I need this help me​
BaLLatris [955]

Answer:

first of all is that really chemistry

3 0
3 years ago
Which part of the mantle is still a solid but flows like a thick, heavy liquid?
marusya05 [52]

Hello!

Your answer is A, asthenosphere

<u>The asthenosphere is a part of the mantle</u>. It helps move the plates in the Earth.

It is <u>below the lithosphere,</u> between <u>80 and 200 km</u> below the surface.

Therfore, the asthenosphere is <u>the part of the mantle that is still a solid but flows like a thick, heavy liquid.</u>

<u />

Hope this helps!

Have a great day!

3 0
3 years ago
Read 2 more answers
Hydrogen sulfide decomposes according to the following reaction: 2H2S(g) ⇋ 2H2(g) + S2(g) Kc=9.30x10-8 at 700.°C.If 0.45 mol of
Natalija [7]

Answer:

[H₂] = 1.61x10⁻³ M

Explanation:

2H₂S(g) ⇋ 2H₂(g) + S₂(g)

Kc = 9.30x10⁻⁸ = \frac{[H_{2}]^2[S_{2}]}{[H_{2}S]^2}

First we <u>calculate the initial concentration</u>:

0.45 molH₂S / 3.0L = 0.15 M

The concentrations at equilibrium would be:

[H₂S] = 0.15 - 2x

[H₂] = 2x

[S₂] = x

We <u>put the data in the Kc expression and solve for x</u>:

\frac{(2x^2) * x}{(0.15-2x)^2}=9.30x10^{-8}

\frac{4x^3}{0.0225-4x^2}=9.30*10^{-8}

We make a simplification because x<<< 0.0225:

\frac{4x^3}{0.0225} =9.30*10^{-8}

x = 8.058x10⁻⁴

[H₂] = 2*x = 1.61x10⁻³ M

5 0
3 years ago
Read 2 more answers
17. Which of the following statement best explains what pollination is?
Anna35 [415]

Answer:

ıt is the projesi where the polen of one flower reaches the sığmaz of another flower.

4 0
3 years ago
Read 2 more answers
7.26 of a hydrate, Cu(NO3)2.xH2O, formed 2.4 g copper(II) oxide.
goldfiish [28.3K]

Number of moles= mass/ molar mass

Or n=m/MM

n = number of moles

m = mass

MM = molar mass

1) n CuO = 2.4g / 79.54g/mol = 0.03 mol CuO

2) n Cu(NO3)2.xH2O = 7.26 g / 205.6 = 0.035 moles of Cu(NO3)2.xH2O

3) 205.6 g

Cu = 63.5 g

N = 14g

O =16g

H= 1 g

63.5+ (14+(16*3))*2+1*2+16 =205.6 g

4) yes is 188g

5) I don’t know, I assume was 1

6 0
3 years ago
Read 2 more answers
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