I do believe the answer is:D.
0 1 2 3
0 and 3 is 3
1 and 2 is 3
Given:
The density of air = 1.19 g/L at 25°C and atmospheric pressure,
or
density = 1.19 x 10⁻³ kg/L
Volume of air in the room is
V = 12.5*19.5*6.0 = 1462.5 ft³
Note that
1 ft³ = 28.317 L
Therefore
V = (1462.5 ft³)*(28.317 L/ft³) = 4.1414 x 10 ⁴ L
By definition, mass = density*volume.
Therefore, the mass is
(1.19 x 10⁻³ kg/L)*(4.1414 x 10⁴ L) = 49.283 kg
Answer: 49.3 kg (nearest tenth)
Answer:
Carbon dioxide ---> CO₂
Water ----> H₂O
Carbon ---> C
Oxygen ----> O₂
Hydrogen ----> H₂
Explanation:
The molecular formula of an element or compound is a formula which represents the composition of a molecule of that element or compound. It consists of the formula representing the atoms present as well as the number of atoms of each element innthe compound written as subscript innthe formula of the element or compound.
The molecular formula of the given elements and compounds are given below:
Carbon dioxide ---> CO₂
Water ----> H₂O
Carbon ---> C
Oxygen ----> O₂
Hydrogen ----> H₂
The molecular formula of carbon dioxide shows that in a molecule of carbon dioxide, there are two atoms of oxygen and one atom of carbon present in a molecule of carbon dioxide.
The molecular formula of water shows that are two atoms of hydrogen and one atom of oxygen present in a molecule of water.
The molecular formula of carbon shows that there are one carbon atoms in a molecule of carbon.
The molecular formula of oxygen shows that there are two oxygen atoms in a molecule of oxygen gas.
The molecular formula of hydrogen shows that there are two molecules of hydrogen in a molecule of hydrogen gas.
First, we need to balance the chemical reaction first.
4P4 + 5S8 -> 4P4S10
Next, we determine the limiting reactant based on the given amounts of the reactants and the stoichiometric ratio of the reactants.
Based on 14.62 mol P4, the P4S10 produced is
16.42 mol P4 (4 mol P4S10 / 4 mol P4) = 16.42 mol P4S10
Based on 2.14 mol S8
2.14 mol S8 (4 mole P4S10 / 5 mol S8) = 1.71 mol P4S10
The maximum amount is 1.71 mol P4S10 since S8 is the limiting reactant.
