Assuming the water is present at 20 °C, the solubility of barium chromate is 0.2275 mg/100 mL
Converting this to mg/L, we get:
2.275 mg/L
Converting this value again, to grams per liter, we get:
0.002275 g/L
To dissolve one gram, we require:
1/0.002275 = 439.56044
440 liters of water.
The answer is 48g
30 x 1.60 = 48
A set of attainable values for some physical quantity such as energy or wavelength
