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Strike441 [17]
3 years ago
11

A solid that form from liquid in a chemical reaction is called

Chemistry
1 answer:
lesantik [10]3 years ago
3 0

precipitate is the answer

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In a solution, the parts of the solution are mixed A) chemically. B) physically. C) only in water. D) by electronic means.
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B. physically i hope this helps

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3 years ago
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What is the half-life of 20 g of a radioactive sample if 5 g remain after 8 minutes?
Anni [7]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 20 g

m (final mass after time T) = 5 g

x (number of periods elapsed) = ?

P (Half-life) = ? (in minutes)

T (Elapsed time for sample reduction) = 8 minutes

Let's find the number of periods elapsed (x), let us see:

m =  \dfrac{m_o}{2^x}

5 =  \dfrac{20}{2^x}

2^x = \dfrac{20}{5}

2^x = 4

2^x = 2^2

\boxed{x = 2}


Now, let's find the half-life (P) of the radioactive sample, let's see:

T = x*P

8 = 2*P

2\:P = 8

P = \dfrac{8}{2}

\boxed{\boxed{P = 4\:minutes}}\Longleftarrow(Half-Life)\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

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3 years ago
What is the solution to the problem to the correct number of significant figures (102,900/12)+(170•1.27)
GarryVolchara [31]

As per as the Multiplication rules of the significant figures, whenever any numbers in the decimals forms are multiplied or divided then result in mentioned in such a way so that the significant figures after the decimal will be same as that in the given least condition.


_______________________________


102900/12 = 8575


170 × 1.27 = 215.9


∴ (102,900 ÷ 12) + (170 × 1.27) =  8575 + 215.9


= 8790.9


Now, As per as Above rules, answer in correct significant figures will be = 8791.



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4 years ago
What would be the volume in liters of 640g of oil if the density of the oil is 0.8g/mL
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Hey there!

Mass = 640 g

Density = 0.8 g/mL

Volume = ?

Therefore:

D = m / V

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The columns of the periodic table, also referred to as "groups" contain elements with similar reactive properties, due to these elements having a similar configuration of electrons in their outer shell.
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