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likoan [24]
4 years ago
10

"A 500-N weight sits on the small piston of a hydraulic machine. The small piston has an area of 2.0 cm2. If the large piston ha

s an area of 40 cm2, how much weight can the large piston support? Assume the pistons each have negligible weight."
Physics
1 answer:
dolphi86 [110]4 years ago
8 0

Answer:

10000 N

Explanation:

F_1 = Force on small piston = 500 N

F_2 = Force on large piston

A_1 = Area of small piston = 2 cm²

A_2 = Area of large piston = 40 cm²

From Pascal's law we have

\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\Rightarrow F_2=\dfrac{F_1A_2}{A_1}\\\Rightarrow F_2=\dfrac{500\times 40}{2}\\\Rightarrow F_2=10000\ N

Weight the large piston can support is 10000 N

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