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3 years ago

Why are there elements on the bottom of the periodic table? What’s the name of this group of elements?

Chemistry

1 answer:

solmaris [256]3 years ago

6 0

Answer

The lanthanides and actinides are separated from the rest of the periodic table, usually appearing as separate rows at the bottom. The reason for this placement has to do with the electron configurations of these elements

Explanation:

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Question 12 A chemistry student must write down in her lab notebook the concentration of a solution of sodium thiosulfate. The c

o-na [289]

Weight of sodium thiosulfate = 76.148 - 8.2

= 67.948 g.

Concentration of the solution = 67.948 / 172.7

= 0.393 g / mL. to the nearest thousandth . (answer).

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4 years ago

ara h 6 complements ara h 2 as an important marker for ige reactivity to peanut audrey e. koid,† martin d. chapman,†

frez [133]

Purified Ara h 6 will be helpful for research into the immunological mechanisms underlying peanut allergy, including molecular and cellular studies, diagnostic IgE antibody testing, and clinical trials.

1.4% of children and 0.6% of adults in the United States suffer from the food allergy peanut. Approximately 1.8% of youngsters in the UK are allergic to peanuts. Food allergies to milk, eggs, and wheat are often outgrown by children, while allergies to peanuts are more persistent and frequently last into adulthood. As little as 0.4 g of peanut is required to cause milder allergic reactions like rashes, angioedema, and gastrointestinal problems. However, peanut is also one of the leading causes of severe, sometimes fatal anaphylactic reactions.

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2 years ago

A sample of gas occupies 6. 8 L at 327 c what will be it volume at 27 c if the pressure and number of particles do not change

Vitek1552 [10]

A sample of gas occupies 6. 8 L at 327 c and the volume at 27 c if the pressure and number of particles do not change is 3.401 L.

<h3>What is volume?</h3>

Volume is a measurement of the three-dimensional space that is occupied. Numerous imperial units or the SI-derived units, such as the cubic meter and liter, are frequently used to quantify it numerically (such as the gallon, quart, cubic inch). Volume and the length (cubed) have a symbiotic relationship. The volume of a container is typically thought of as its capacity, not as the amount of the space it takes up. In the other words, the volume is the amount of fluid (liquid or gas) that the container may hold.

Volume was initially measured using naturally occurring vessels of a comparable shape and then with standardized containers. Arithmetic formulas can be used to quickly calculate the volume of the several straightforward three-dimensional shapes. If a formula for shape's boundary is known, it is possible to use integral calculus to determine the volumes of more complex shapes. No object in dimensions of zero, one, or two has volume; in the dimensions of four and above, the hypervolume is a concept similar to the standard volume.

In solving the any gas law problems, kelvin temperature will be used.

kelvin = degree celsius + 273.15

Kelvin = 327 + 273.15

= 600.15 K

Kelvin = 27 + 273.15

= 300.15 K

Given Data;

$V_{1}$ (the initial volume) = 6.8 L $V_{2}$ (the final volume) = ? unknown

$T_{1}$ (the initial temperature = 327 °C $T_{2}$ (the final temperature) = 27 °C

=( 600.15 K) = (300.15 K)

This problem can be solve using the Charles' Law which states that volume is directly proportional to kelvin temperature of gases if amount of gas and pressure are constant. If the temperature decreases, volume decreases.

Formula of the Charles' Law is $\frac{V_{1} }{T_{1} }= \frac{V_{2} }{T_{2} }$

To solve for V2, we can used formula $V_{2} =\frac{V_{1}T_{2} }{T_{1} }$

$V_{2} =\frac{V_{1}T_{2} }{T_{1} }$

= 6.8 L × 300.15 K / 600.15 K (cancel the unit kelvin)

= 2041.02 L / 600.15

$V_{2}$ = 3.401 L

Therefore, volume is 3.401 L

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1 year ago

Is the slight bending of light as it passes around the edge of an object.

Snezhnost [94]

The answer to the question Retraction. Its because the light goes around it

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4 years ago

Write the electron configurations for each of the following elements:

Stolb23 [73]

Answer:

(a) E.C - 2,8,8,3
(b) E.C - 2,8,8,4
(c) E.C - 2,8,8,6
(d) E.C - 2,8,8,8
(e) E.C - 2,8,8,8,18

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4 years ago