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Basile [38]
3 years ago
5

What is the total number of moles of O2(g) that must react completely with 5.00 moles of C4H10(g)?

Chemistry
1 answer:
Naddika [18.5K]3 years ago
4 0

Answer:

32.5 moles of O2(g) are necessaries for a complete reaction

Explanation:

Based on the reaction of combustion of C4H10(g):

C4H10(g) + 13/2 O2(g) → 4CO2(g) + 5H2O(g)

<em>1 mole of C4H10 needs 13/2 moles O2 for a complete reaction.</em>

<em />

That means, the moles of O2 required for a reaction of 5.00 moles of C4H10 are:

5.00 moles C4H10 * (13/2mol O2 / 1mol C4H10) =

32.5 moles of O2(g) are necessaries for a complete reaction

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6 0
4 years ago
If 1.20 moles of copper react with mercuric nitrate how many moles of mercury form
Andrej [43]
Reaction of Copper with Mercuric Nitrate is as follow,

                       Cu  +  Hg(NO₃)₂    →    Cu(NO₃)₂  +  Hg

According to equation,

                            1 Mole of Cu reacts to form  =  1 Mole of Hg

So,

           1.20 Moles of Cu will react to produce  =  X Moles of Hg

Solving for X,

                                   X  =  (1.20 mol × 1 mol) ÷ 1 mol

                                   X  =  1.20 mol of Hg
Result:
          1.20 mole of Cu when reacted with mercuric nitrate produces 1.20 moles of Hg.
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4 years ago
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3 years ago
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Answer:

Answer

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3 years ago
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