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makkiz [27]
3 years ago
5

Two charges attract each other with a force of 3.0 n. what will be the force if the distance between them is reduced to one-nint

h of its original value?
Physics
1 answer:
Schach [20]3 years ago
5 0
The electrostatic force between two charges is given by
F= k_e  \frac{q_1 q_2}{d^2}
where ke is the Coulomb's constant, q1 and q2 are the two charges and d is the distance between the two charges.
We can see from the formula that the force is proportional to \frac{1}{d^2}. This means that if we reduce the distance to one-ninth, i.e. the new distance is
d_{new} =  \frac{1}{9}d
then the force will scale as
 \frac{1}{(d_{new})^2}= \frac{1}{( \frac{1}{9} )^2d^2}= \frac{81}{d^2}
So, the new force will be 81 times stronger than the initial value, therefore the new force is
F_{new}=81 F=81 \cdot 3.0 N=243 N
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The ratio of the potential difference across a conductor to the current in the conductor is called
svetoff [14.1K]

Answer:

The ratio of the potential difference across a metallic conductor to the current in the conductor is known as.

B. Resistance.

Explanation:

According to ohms law   " the current  passing through a conductor is directly proportional to the potential difference between the ends provided the temperature of the wire remains constant".

What is resistance ?

Resistance is a measure of the opposition to current flow in an electrical circuit

what is a resistor ?

a resistor is a n electric conductor which forms resistance to free flow of electric current, the resistance is measured in Ω

3 0
3 years ago
Consider a semi-spherical bowl machined out of wood (A drawing of a semi-spherical bowl can be found in UNIT- 4 Introduction, so
Mrrafil [7]

Answer:

The total surface are of the bowl is given by: 0.0532*pi m² (approximately 0.166533 m²)

Explanation:

The total surface area of the semi-spherical bowl can be decomposed in three different sections: 1) an outer semi-sphere of radius 12 cm, 2) an inner semi-sphere of radius 10 cm, and 3) the edge, which is a 2-dimensional ring with internal radius of 10 cm and external radius of 12 cm. We will compute the areas independently and then sum them all.

a) Outer semi-sphere:

A1 = 2*pi*r² = 2*pi*(12 cm)² = 288*pi cm² = 904.78 cm²

b) Inner semi-sphere:

A2 = 2*pi*(10 cm)² = 200*pi cm² = 628.32 cm²

c) Edge (Ring):

A3 = pi*(r1² - r2²) = pi*((12 cm)²-(10 cm)²) = pi*(144-100) cm² = 44*pi cm² = 138.23 cm²

Therefore, the total surface area of the bowl is given by:

A = A1 + A2 + A3 = 288*pi cm² + 200*pi cm² + 44*pi cm² = 532*pi cm² (approximately 1665.33 cm²)

Changing units to m², as required in the problem, we get:

A = 532*pi cm² * (1 m² / 10, 000 cm²) = 0.0532*pi m² (approximately 0.166533 m²)

5 0
3 years ago
You stand on a frictional platform that is rotating at 1.1 rev/s. Your arms are outstretched, and you hold a heavy weight in eac
bezimeni [28]

Answer:

a) The resulting angular speed of platform is 1.38 rev/sec

b) The change in kinetic energy of the system is 53 J.

Explanation:

This question is incomplete. The complete question will be:

You stand on a frictional platform that is rotating at 1.1 rev/s. Your arms are outstretched, and you hold a heavy weight in each hand. The moment of inertia of you, the extended weights, and the platform is 8.8 kg · m2. When you pull the weights in toward your body, the moment of inertia decreases to  7.0 k g .m 2  

a) What is the resulting angular speed of the platform? Answer in units of r e v / s .

b)What is the change in kinetic energy of the system? Answer in units of J.

<h3>ANSWER:</h3>

a)

we know that:

Angular Momentum = L = Iω

From conservation of momentum:

Lo = Lf

(Io) (ωo) = (If) (ωf)

ωf = (Io) (ωo)/(If)

ωf = (8.8 kg.m²)(1.1 rev/s)/(7.0 kg.m²)

<u>ωf = 1.38 rev/sec =</u>

b)

ωf = (1.38 rev/sec)(2π rad/ 1 rev) = 8.67 rad/sec

ωo = (1.1 rev/sec)(2π rad/ 1 rev) = 6.91 rad/sec

The kinetic energy for rotational motion is given as:

K.E = (1/2)Iω²

Thus, the change in kinetic energy will be:

ΔK.E = (K.E)f - (K.E)o

ΔK.E = (1/2)Ifωf² - (1/2)Ioωo²

ΔK.E = (1/2)(Ifωf² - Ioωo²)

ΔK.E = (1/2)[(7 kg.m²)(8.67 rad/sec)² - (8.8 kg.m²)(6.91 rad/sec)²

<u>ΔK.E = 53 J</u>

5 0
3 years ago
A 230.-mL sample of a 0.240 M solution is left on a hot plate overnight; the following morning, the solution is 1.75 M. What vol
Gwar [14]

Answer:

The volume of water evaporated is 199mL

Explanation:

Concentration is calculated with the following formula

C=\frac{n}{V}

where n is the number of moles of solute and V is the volume of the solution (in this case is the same as the solvent volume) in liters.

So we isolate the variable n to know the amount of moles, using the volume given in liters

230mL=0.23L

n=C*V=0.240 M*0.23L=0.055 mol

Now, we isolate the variable V to know the new volume with the new concentration given.

V=\frac{n}{C} =0.055mol/1.75M=0.031L=31mL

Finally, the volume of water evaporated is the difference between initial and final volume.

V_{ev}= V_{i} -V_{f} =230mL-31mL=199mL

4 0
3 years ago
What are the products of the double-replacement reaction between potassium bromide and silver nitrate? Name the resulting compou
timofeeve [1]

Explanation:

A double replacement reaction is a reaction in which two different compounds are mixed together and both their cations and anions get exchanged with each other respectively.

When potassium bromide reacts with silver nitrate then it results in the formation of potassium nitrate and silver bromide.

The chemical reaction equation is as follows.

        KBr + AgNO_{3} \rightarrow KNO_{3} + AgBr

6 0
3 years ago
Read 2 more answers
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