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3 years ago

Positively charged ions are surrounded by freely moving electrons in

Physics

1 answer:

ASHA 777 [7]3 years ago

3 0

I believe the answer would be valence shells

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_________ changes from day to day, while ____________ changes from region to region. A) climate, weather B) weather, climate C)

vladimir2022 [97]

B) Weather changes day to day, while climate changes region to region.

Climate is the weather in a certain area. It's usually the average weather over a long period of time

Weather is in shorter terms then climate

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0

3 years ago

Read 2 more answers

What are the structures shown below ??

forsale [732]

The body system on the chart

8 0

4 years ago

A fairground ride consists of a large vertical drum that spins so

expeople1 [14]

Answer:

v = 3.84 m/s

Explanation:

In order for the riders to stay pinned against the inside of the drum the frictional force on them must be equal to the centripetal force:

$Centripetal\ Force = Frictional\ Force\\\\\frac{mv^2}{r} = \mu R = \mu W\\\\\frac{mv^2}{r} = \mu mg\\\\\frac{v^2}{r} = \mu g\\\\v = \sqrt{\mu gr}$

where,

v = minimum speed = ?

g = acceleration due to gravity = 9.81 m/s²

r = radius = 10 m

μ = coefficient of friction = 0.15

Therefore,

$v=\sqrt{(0.15)(9.81\ m/s^2)(10\ m)}$

6 0

3 years ago

A wire with a length of 150 m and a radius of 0.15 mm carries a current with a uniform current density of 2.8 x 10^7A/m^2. The c

Mrac [35]

Answer:

The current is 2.0 A.

(A) is correct option.

Explanation:

Given that,

Length = 150 m

Radius = 0.15 mm

Current density $J=2.8\times10^{7}\ A/m^2$

We need to calculate the current

Using formula of current density

$J = \dfrac{I}{A}$

$I=J\timesA$

Where, J = current density

A = area

I = current

Put the value into the formula

$I=2.8\times10^{7}\times\pi\times(0.15\times10^{-3})^2$

$I=1.97=2.0\ A$

Hence, The current is 2.0 A.

7 0

3 years ago

In just 0.30 s , you compress a spring (spring constant 5000 n/m ), which is initially at its equilibrium length, by 4.0 cm. par

Ierofanga [76]

The average power output is the ratio between the work done to compress the spring, W, and the time taken, t:
$P= \frac{W}{t}$ (1)

The work done is equal to the elastic energy stored by the compressed spring:
$W=U= \frac{1}{2}kx^2$
where $k=5000 N/m$ is the spring constant and $x=4.0 cm=0.04 m$ is the compression of the spring. If we substitute the numbers, we find:
$W= \frac{1}{2}(5000 N/m)(0.04 m)^2=4 J$

And now we can use eq.(1) to calculate the average power output:
$P= \frac{W}{t}= \frac{4 J}{0.30 s} =13.3 W$

7 0

3 years ago