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NikAS [45]
4 years ago
15

Cytosine is always joined to what is the answer

Chemistry
1 answer:
Sholpan [36]4 years ago
5 0

<u>Cytosine </u>is always joined with <u>Guanine.</u>

<em>The pyrimidine cytosine (C) always pairs with the purine guanine (G).</em>

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The density of water is 1.0 g/cm3. Which of the following substances will sink in water?
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IV. Molasses will sink because it has a greater density. The rest will float or suspend.
8 0
4 years ago
er solutions can be produced by mixing a weak acid with its conjugate base or by mixing a weak base with its conjugate acid. The
liubo4ka [24]

Answer:

You need to add 19,5 mmol of acetates

Explanation:

Using the Henderson-Hasselbalch equation:

pH = pKa + log₁₀ [base]/[acid]

For the buffer of acetates:

pH = pKa + log₁₀ [CH₃COO⁻]/[CH₃COOH]

As pH you want is 5,03, pka is 4,74 and milimoles of acetic acid are 10:

5,03 = 4,74 + log₁₀ [CH₃COO⁻]/[10]

1,95 = [CH₃COO⁻]/[10]

<em>[CH₃COO⁻] = 19,5 milimoles</em>

Thus, to produce an acetate buffer of 5,03 having 10 mmol of acetic acid, you need to add 19,5 mmol of acetates.

I hope it helps!

7 0
4 years ago
A function of a cell membranes in humans is the
r-ruslan [8.4K]
<span>A cell membrane protects the structures within the cell. They are semipermeable which means that only certain objects are able to pass through them. They also give shape to the cell and support its structure. </span>
4 0
3 years ago
A solution consists of 35.00 g of CuSO4 dissolved in 250.0 mL of water. The molar mass of Cu is 63.55 g/mol the molar mass of S
8_murik_8 [283]

Answer:

0.87708moldm-3

Explanation:

molar \: mass \: of \: cuso4 = 63.55 + 32.07 + 4(16.00) \\  =159.62gmol {}^{ - 1}   \\ mole(n) =  \frac{mass}{molar \: mass }  \\ n =  \frac{35}{159.62}  \\ n = 0.21927mol \\ molarity =  \frac{n}{v}  \\ molarity =  \frac{0.21927}{0.25} \\ molarity = 0.87708moldm {}^{ - 3}

3 0
2 years ago
If it takes 0.0393 L of oxygen gas kept in a cylinder under pressure to fill an evacuated 1.05 L reaction vessel in which the pr
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Answer:

26.2 atm

Explanation:

P1=P2V2/V1

P1=(1.05 x .980)/.0393

Answer: 26.2 atm

You can check this by knowing that P and V at constant T have an inverse relationship. Hence, this is correct.

5 0
3 years ago
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