I think the half of 1293 its the mass ? maybe idk I just tried
A rock is definitely more dense. If you were to put a cloud in water it would float/stay above it and a rock would sink to the bottom
Answer:
2.1056L or 2105.6mL
Explanation:
We'll begin by calculating the number of mole in 10g of Na2CO3. This can be obtained as follow:
Molar mass of Na2CO3 = (23x2) + 12 + (16x3) = 106g/mol
Mass of Na2CO3 = 10g
Mole of Na2CO3 =.?
Mole = mass /molar mass
Mole of Na2CO3 = 10/106
Mole of Na2CO3 = 0.094 mole
Next, we shall determine the number of mole CO2 produced by the reaction of 0.094 mole of Na2CO3. This is illustrated below:
Na2CO3 + 2HCl —> 2NaCl + H2O + CO2
From the balanced equation above,
1 mole of Na2CO3 reacted to produce 1 mole of CO2.
Therefore, 0.094 mole of Na2CO3 will also react to 0.094 mole of CO2.
Next, we shall determine the volume occupied by 0.094 mole of CO2 at STP. This is illustrated below:
1 mole of a gas occupy 22.4L at STP. This implies that 1 mole CO2 occupies 22.4L at STP.
Now, if 1 mole of CO2 occupy 22.4L at STP, then, 0.094 mole of CO2 will occupy = 0.094 x 22.4 = 2.1056L
Therefore, the volume of CO2 produced is 2.1056L or 2105.6mL
Hello!
Numbers from -998 and 999 are in between -999 and 1000.
I hope this was helpful! c:
Name Bromine
Symbol Br
Atomic Number 35
Atomic Mass 79.904 atomic mass units
Number of Protons 35
Number of Neutrons 45
Number of Electrons 35
Melting Point -7.2° C
Boiling Point 58.78° C
Density 3.119 grams per cubic centimeter
Normal Phase Gas
Family Halogens
Period 4
Cost $4.90 per 100 grams
