Answer:
See Explanation
Explanation:
Resonance is a valence bond terminology which is used to describe a situation in which a single structure is not able to fully describe the nature of bonding in a molecule.
In such cases, we invoke more than one structure. Each structure contributes significantly to our understanding of the nature of bonding in the molecule under consideration and these structures are called canonical or resonance structures.
The real structure of the molecule is somewhere in between these structures - a resonance hybrid.
For ozone, two equivalent structures can be used to describe the bonding in the molecule. These structures are equivalent as shown in the mage attached. We can see from these structures that the bond order in ozone is 1.5(one and half bonds)
I am not sure but rocky bodies ranging from large to small in size
The volume of CO2 at STP =124.298 L
<h3>Further explanation</h3>
Given
Reaction
4 KMnO4, +4 C3H5(OH)5, -7K2CO3, + 7 Mn2O3, +5 CO2, + 16 H2O
701,52 g of KMnO4
Required
volume of CO2 at STP
Solution
mol KMnO4 (MW=158,034 g/mol) :
mol = mass : MW
mol = 701.52 : 158.034
mol = 4.439
mol CO2 from equation : 5/4 x mol KMnO4 = 5/4 x 4.439 = 5.549
At STP 1 mol = 22.4 L, so for 5.549 moles :
=5.549 x 22.4
=124.298 L
I would say the answer is P2O5. Some teachers use PO2.5. I'm not one of them.
The molar mass of the compound:
If the solution has an osmotic pressure of 8.44 torr, then the molar mass of the unknown non-electrolyte is 223.14 g.
What is osmosis?
- Osmosis is defined as the flow of solvent molecules through semi-permeable membrane.
- Osmotic pressure is the pressure applied to stop the flow of solvent molecules.
- It is a colligative property that means osmotic pressure depends on the number of solute particles .
Therefore,
π
( for electrolytes)
Where, π= Osmotic pressure
i = Van 't Hoff factor
n= moles
R= Gaseous constant = 62.363577 L torr 
T= Temperature
V= Volume of solution
Given:
T= 298K
V= 150 mL= 0.150 L
Given mass of unknown electrolyte= 15.2 mg = 15.2 x 
g
Osmotic pressure= 8.44 torr
Molar mass= ?
For non-electrolytes:
πV = n RT
πV=
RT
Calculations:
Putting the given values in the formula:
8.44 x 0.150 =15.2 x / M x 62.36 x 298
1.266 = 282.5/M
M = 282.5/1.266
M = 223.14 g
Therefore,
The molar mass of the unknown non-electrolyte is 223.14g.
Learn more about Osmotic pressure here,
brainly.com/question/13680877
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