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yarga [219]
3 years ago
12

How can you improve the percent yield of copper in this lab? Check all possible strategies that will help you do so.

Chemistry
2 answers:
Paladinen [302]3 years ago
8 0

Measure reactants precisely.

Stir to help the reaction take place.

Wait patiently until the reaction completes.

Make sure to recover as much copper as possible.

Explanation:

Anything that increases the rate of this reaction will improve the yield of copper production.

The rate of reaction is usually a factor of how the concentration of reactants and products changes with time.

Some of the factors that affects the rate of a reaction are:

  • Nature of reactants
  • concentration or pressure if gases
  • temperature
  • presence of catalysts
  • degree of mixing

In this reaction:

  • to ensure we have the maximum amount of copper produced, measure out the exact/accurate amount of reactants stated
  • make sure you stir the reactants to ensure they mix and combine.
  • ensure you are not too much in haste. Wait for the reaction to go into completion.
  • recover as much copper as possible

learn more:

Chemical reaction brainly.com/question/6281756

#learnwithBrainly

FrozenT [24]3 years ago
7 0

answer: Measure reactants precisely, Stir to help the reaction take place, and Wait patiently until the reaction completes.

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What mass of iron is formed when 10 grams of carbon react with 80 grams of iron iii oxide?
yKpoI14uk [10]

Answer:

55.85 grams of Fe is formed.

Explanation:

Identify the reaction:

2Fe₂O₃  +  3C  →  4Fe  +  3CO₂

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2 moles of oxide need 3 moles of C, to react

0.5 moles of oxide, will need ( 0.5  . 3)/ 2 = 0.751 mol

I have 0.83 moles of C, so C is the excess.

The limiting is the oxide.

3 mol of C need 2 mol of oxide to react

0.83 mol of C, will need (0.83  . 2)/ 3 = 0.553 mol of oxide, and I only have 0.5 (That's why Fe₂O₃ is the limiting)

Ratio is 2:4 (double)

If I have 0.5 moles of oxide, I will produce the double, in the reaction.

1 mol of Fe, will be produce so its mass is 55.85 g

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Answer:

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