Use two different methods to solve the following equations for x and y? 4x+2y=22 -2x+2y=-8
1 answer:
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The x-intercepts of the parabola are (3, 0) and (7,0)
<h3>How to determine the x-intercept?</h3>The given parameters are:
Vertex (h, k) = (5, -12)
Point (x, y) = (0, 63)
The equation of a parabola is:
y = a(x - h)^2 + k
Substitute (h, k) = (5, -12)
y = a(x - 5)^2 - 12
Substitute (x, y) = (0, 63)
63 = a(0 - 5)^2 - 12
Evaluate
63 = 25a - 12
Add 12 to both sides
25a = 75
Divide by 26
a = 3
Substitute a = 3 in y = a(x - 5)^2 - 12
y = 3(x - 5)^2 - 12
Set y to 0 to determine the x-intercepts
0 = 3(x - 5)^2 - 12
Add 12 to both sides
3(x - 5)^2 = 12
Divide by 3
(x - 5)^2 = 4
Take the square root of both sides
Add 5 to both sides
Expand
x = (5 - 2, 5 + 2)
Evaluate
x = (3, 7)
Hence, the x-intercepts of the parabola are (3, 0) and (7,0)
Read more about parabola at:
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Answer:
The probability that a high school member selected at random is on the swim team is
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: High school student.
Event B: Is on the swin team.
Probability of selecting a high school student:
Of the 1500 students, 200 are on high school. So
Probability of selecting a high school student who swims:
Of the 1500 students, 45 are high school students who swim. So
What is the probability that a high school member selected at random is on the swim team?
The probability that a high school member selected at random is on the swim team is