Answer:
a.)1.)12m/s
2.)12m/s
3.)7m/s
4.)7m/s
5.)14m/s
6.)0m/s
b.)1.) 3m/s^2
2.)1.71m/s^2
3.).58m/s^2
4.).39m/s^2
5.).70m/s^2
6.)0
c.)1.)48m
2.)84m
3.)84m
4.)126m
5.)280m
6.)suma todos los metros mas 98m y obtendras la distancia en cual el carro se para
Explanation:
vinicial=0m/s
tiempo inicial=0s
Intervalo 1
v=12m/s
t=4s
aceleracion= vf-vi/t
=12-0/4
=12/4=3m/s^2
Intervalo 2
v=12m/s
t=7s
a=12/7
Intervalo 3
v=7m/s
t=12s
a=7/12
Intervalo 4
v=7m/s
t=18s
a=7/18
Intervalo 5
v=14m/s
t=20s
a=14/20
Intervalo 6
v=0m/s
t=27s
a=0/27
Explanation:
It is given that,
Mass of platinum bar, m = 750 g
Length of the bar, l = 5 cm
Breadth of the bar, b = 4 cm
Width of the bar, h = 1.5 cm
Volume of the bar, 

We need to find the density of the platinum bar. The density of any substance is given by :



So, the density of the platinum bar
. Hence, this is the required solution.
Answer:
Explanation:
Using Snell's law
n₁ sinθ₁ = n₂ sinθ₂
for 420 nm wavelength
where n₁ = 1.00 ( refractive index of air) and θ₁ = 30° n₂ = 1.660
1.00 × sin 30° = 1.660 sinθ₂
sinθ₂ = 0.3012
θ₂ = sin⁻¹ 0.3012 = 17.53°
for 690 nm wavelength
n₁ sinθ₁ = n₂ sinθ₂
sinθ₂ = 0.5 / 1.630
θ₂ = sin⁻¹ 0.3067 = 17.86°
the angle between the two beam = 17.863° - 17.53° = 0.333°
Answer:
Velocity will be equal to 7.31 m/sec
Explanation:
We have given mass of the student m = 61 kg
Height of the water slide h = 12.3 m
Acceleration due to gravity 
Potential energy is equal to 
Work done due to friction = -5800 J
So energy remained = 7352.94-5800 = 1552.94 J
This energy will be equal to kinetic energy
So 


v = 7.13 m/sec
PE=mgh=150kg*9.8m/c² *50m=73500 J
W=F*d=mgd = 2.5*9.8*3.0 = 73.7J
W=mgh=68.0*7.62*9.8 =50.78 J
150 lb = 68.0 kg
25 ft = 7.62m