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klemol [59]
4 years ago
14

What is the weight of a 24.52kg Television dropped on pluto(acceleration of 0.59m/s/s)?

Physics
2 answers:
jolli1 [7]4 years ago
6 0
W=ma=24.52*0.59 = ...

ella [17]4 years ago
6 0

Answer:

14.47 Newtons

Explanation:

Hello

The weight of an object is the force of gravity on the object and can be defined as the product of mass by the acceleration of gravity, w = mg

for example

a person with mass of 80 kilograms on earth where the acceleration of gravity is 9.8 m/s2  weigh.

w=mg

W=80kg*9.8 m/s2

W=784 Newtons

Now, let see the data we have about the question

W=mg\\W=24.52 kg* 0.59 \frac{m}{s^{2} } \\W=14.47\ Newtons

the weight is 14.47 N

Have a great day

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Alguien me podria ayudar con esto pliz.. Ahora resuelva el siguiente ejercicio, tenga presente lo visto en clase y aprendido en
creativ13 [48]

Answer:

a.)1.)12m/s

2.)12m/s

3.)7m/s

4.)7m/s

5.)14m/s

6.)0m/s

b.)1.) 3m/s^2

2.)1.71m/s^2

3.).58m/s^2

4.).39m/s^2

5.).70m/s^2

6.)0

c.)1.)48m

2.)84m

3.)84m

4.)126m

5.)280m

6.)suma todos los metros mas 98m y obtendras la distancia en cual el carro se para

Explanation:

vinicial=0m/s

tiempo inicial=0s

Intervalo 1

v=12m/s

t=4s

aceleracion= vf-vi/t

=12-0/4

=12/4=3m/s^2

Intervalo 2

v=12m/s

t=7s

a=12/7

Intervalo 3

v=7m/s

t=12s

a=7/12

Intervalo 4

v=7m/s

t=18s

a=7/18

Intervalo 5

v=14m/s

t=20s

a=14/20

Intervalo 6

v=0m/s

t=27s

a=0/27

7 0
3 years ago
PLZ ANSWER ASAP!!!!!!!
jenyasd209 [6]

Explanation:

It is given that,

Mass of platinum bar, m = 750 g

Length of the bar, l = 5 cm

Breadth of the bar, b = 4 cm

Width of the bar, h = 1.5 cm

Volume of the bar, V=l\times b\times h

V=5\times 4\times 1.5=30\ cm^3

We need to find the density of the platinum bar. The density of any substance is given by :

d=\dfrac{m}{V}

d=\dfrac{750\ g}{30\ cm^3}

d=25\ g/cm^3

So, the density of the platinum bar 25\ g/cm^3. Hence, this is the required solution.

4 0
3 years ago
A certain kind of glass has an index of refraction of 1.660 for blue light of wavelength 420 nm and an index of 1.630 for red li
Bogdan [553]

Answer:

Explanation:

Using Snell's law

n₁ sinθ₁ = n₂ sinθ₂

for 420 nm wavelength

where n₁ = 1.00 ( refractive index of air) and θ₁ = 30° n₂ = 1.660

1.00 × sin 30° = 1.660 sinθ₂

sinθ₂ = 0.3012

θ₂ = sin⁻¹ 0.3012 = 17.53°

for 690 nm wavelength

n₁ sinθ₁ = n₂ sinθ₂

sinθ₂ = 0.5 / 1.630

θ₂ = sin⁻¹ 0.3067 = 17.86°

the angle between the two beam = 17.863° - 17.53° = 0.333°

7 0
3 years ago
A student, starting from rest, slides down a water slide. On the way down, a kinetic frictional force (a nonconservative force)
katen-ka-za [31]

Answer:

Velocity will be equal to 7.31 m/sec

Explanation:

We have given mass of the student m = 61 kg

Height of the water slide h = 12.3 m

Acceleration due to gravity g=9.8m/sec^2

Potential energy is equal to U=mgh=61\times 9.8\times 12.3=7352.94J

Work done due to friction = -5800 J

So energy remained = 7352.94-5800 = 1552.94 J

This energy will be equal to kinetic energy

So \frac{1}{2}mv^2=1552.94

\frac{1}{2}\times 61\times v^2=1552.94

v^2=50.91

v = 7.13 m/sec

7 0
3 years ago
A 150 kg mass is on a cliff 50 m high. What is its potential energy? 9 How much work is done moving a 2.5 kg book to a shelf 3.0
Mumz [18]
PE=mgh=150kg*9.8m/c² *50m=73500 J

W=F*d=mgd = 2.5*9.8*3.0 = 73.7J

W=mgh=68.0*7.62*9.8 =50.78 J
150 lb = 68.0 kg
25 ft = 7.62m
4 0
4 years ago
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