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klemol [59]
3 years ago
14

What is the weight of a 24.52kg Television dropped on pluto(acceleration of 0.59m/s/s)?

Physics
2 answers:
jolli1 [7]3 years ago
6 0
W=ma=24.52*0.59 = ...

ella [17]3 years ago
6 0

Answer:

14.47 Newtons

Explanation:

Hello

The weight of an object is the force of gravity on the object and can be defined as the product of mass by the acceleration of gravity, w = mg

for example

a person with mass of 80 kilograms on earth where the acceleration of gravity is 9.8 m/s2  weigh.

w=mg

W=80kg*9.8 m/s2

W=784 Newtons

Now, let see the data we have about the question

W=mg\\W=24.52 kg* 0.59 \frac{m}{s^{2} } \\W=14.47\ Newtons

the weight is 14.47 N

Have a great day

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Answer:

J for impulse

t for time

F for force

formula is J=F×t

Explanation:

putting values in eqs after rearranging

we need to find force so

F=J ÷t

F=400÷15

=26.67

=27(rounded off)

27N is the Force applied.

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Explanation:

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3 years ago
When planning an experiment, a scientist must first choose a question to investigate. In an experiment, Renata changes the relea
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Answer:

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6. Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast
nata0808 [166]
<h3><em><u>given</u></em><em><u>:</u></em></h3>

<em><u>first</u></em><em><u> </u></em><em><u>trip</u></em><em><u>=</u></em><em><u> </u></em><em><u>5</u></em><em><u>0</u></em><em><u> </u></em><em><u>miles</u></em><em><u>.</u></em>

<em><u>second</u></em><em><u> </u></em><em><u>trip</u></em><em><u>=</u></em><em><u> </u></em><em><u>3</u></em><em><u>0</u></em><em><u>0</u></em><em><u> </u></em><em><u>miles</u></em><em><u>.</u></em>

<h3><em><u>to</u></em><em><u> </u></em><em><u>find</u></em><em><u>:</u></em></h3>

<em><u>his</u></em><em><u> </u></em><em><u>new</u></em><em><u> </u></em><em><u>time</u></em><em><u> </u></em><em><u>compared</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>old</u></em><em><u> </u></em><em><u>time</u></em><em><u>.</u></em>

<h3><em><u>solution</u></em><em><u>:</u></em></h3>

<em><u>Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.</u></em>

<em><u>Speed = Distance/Time</u></em>

<em><u>So, times taken to covered a distance of 50 miles on his first trip = 50/x hr.</u></em>

<em><u>= 100/x hr</u></em>

<em><u>Therefore</u></em><em><u>,</u></em><em><u> </u></em><em><u>his new time compared with the old time was twice as much.</u></em>

<em><u>answer</u></em><em><u>=</u></em><em><u> </u></em><em><u>b</u></em><em><u>)</u></em><em><u> </u></em><em><u>twice</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>much</u></em>

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