Answers:
kinetic energy lost = 86.4J
Explanation:
let Kf be the kinetic energy after the collision and Ki be the kinetic energy before the collision. let the 3kg car be 1 and 2kg car be 2.
Kf = K1(f) + K2(f)
Ki = K1(i) + k2(i)
loss in kinetic energy = Kf - Ki
= 1/2(3)(2.20)^2 + 1/2(2)(2.20)^2 - 1/2(3)(7)^2 - 1/2(2)(-5)^2
= 12.1 - 98.5
= -86.4 J
therefore, the kinetic energy lost in the collision is 86.4 J.
Answer:
angular resolution = 0.07270° = 1.269 × 
rad
greatest distance from the camera = 118.20 m = 0.118 km
Explanation:
given data
diameter = 0.50 mm = 0.5 × m
distance apart = 15 cm = 15× 
m
wavelength λ = 520 nm = 520 × 
m
to find out
angular resolution and greatest distance from the camera
solution
first we expression here angular resolution that is
sin θ = 
.......................1
put here value λ is wavelength and d is diameter
we get
sin θ = 
θ = 0.07270° = 1.269 × rad
and
distance from camera is calculate here as
θ = 
.................2
I = 
I = 118.20 m = 0.118 km
Melting freezing and boiling are molecular changes
The correct answer is to dissipate energy. Each step in any energy conversion process will dissipate energy. The energy conversion is the process in which a form of energy is being converted into a new or another form of energy.
Answer: 2859.78 k
Explanation: By using the law of conservation of energy, the kinetic energy of the meteor equals the heat energy.
Kinetic energy = 1/2mv^2
Heat energy = mcΔθ
Where m = mass of meteor , v = velocity of meteor = 1623 m/s
c = specific heat capacity of meteor (iron) = 460.548 j/kg/k
Δθ = change in temperature of meteor = ?
From law ofconservation of energy, we have that
1/2mv^2 = mcΔθ
By cancelling "m" on both sides, we have that
v^2/2 = cΔθ
v^2 = 2cΔθ
(1623)^2 = 2× 460.548 × Δθ
2634129 = 921.096 × Δθ
Δθ = 2634129 / 921.096
Δθ = 2859.78 k
