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worty [1.4K]
2 years ago
11

Suppose a person whose mass is m is being held up against the wall with a constant tangential velocity v greater than the minimu

m necessary. Find the magnitude of the frictional force between the person and the wall
Physics
1 answer:
Likurg_2 [28]2 years ago
7 0

Answer:

Explanation:

The man is moving on a circular path . The reaction of wall is providing centripetal force .so

R = mv² / r

Frictional force = μR where  μ is coefficient of friction

= μ x mv² / r

Frictional force = μ x mv² / r

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Mariana [72]
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7 0
2 years ago
Can anybody help me solve this problem? Thank you so much!
ser-zykov [4K]
Please ignore my comment -- mass is not needed, here is how to solve it. pls do the math

at bottom box has only kinetic energy
ke = (1/2)mv^2
v = initial velocity
moving up until rest work done = Fs
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s = distance travel = h/sin(a)
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4 0
2 years ago
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