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labwork [276]
3 years ago
12

Rounding What is 13.428 to the nearest tenths positions

Physics
1 answer:
s2008m [1.1K]3 years ago
8 0
The answer is 13.4 rounded to the nearest tenth
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The animation shows a ball which has been kicked upward at an angle. Run the animation to watch the motion of the ball. Click in
sergejj [24]

Answer:

The acceleration of the ball is  a_y =  - 0.3672 \ m/s^2

Explanation:

From the question we are told that

       The maximum height the ball reachs is H_{max} =  42.24 \ m

       The horizontal component of the initial velocity of the ball is v_{ix} = 5.57 \ m/s

       The vertical component of the initial velocity of the ball is v_{iy} = = 16.18 m/s

The vertically motion of the ball can be mathematically represented as

       v_{fy}^2  =  v_{iy} ^2 + 2 a_{y} H_{max}

Here the final velocity at the maximum height is zero so v_{fy} = 0 \ m/s

Making the acceleration a_y the subject we have

        a_y =  \frac{v_{iy} ^2}{2H_{max}}

substituting values

      a_y =  - \frac{5.57^2}{2* 42.24}

      a_y =  - 0.3672 \ m/s^2

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Static friction and normal force? I would Google to double check if I'm right.

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