Answer:
The period is
Explanation:
From the question we are told that
The mass is
The extension of the spring is
The spring constant for this is mathematically represented as
Where F is the force on the spring which is mathematically evaluated as
So
The period of oscillation is mathematically evaluated as
substituting values
The period is 1/5 second, and the frequency is 5 Hz.
Explanation:
Let's start by reviewing some definitions about waves:
- The period of a wave is the time taken for the wave to make one complete cycle. It is indicated with T and it is measured in seconds (s)
- The frequency of a wave is the number of complete cycles made by the wave in one second. It is indicated with f and it is measured in Hertz (Hz). It is equal to the reciprocal of the period:
where f is the frequency and T is the period.
In this problem, we have a wave that passes a given point five time per second. This means that the number of oscillations per second is five, and so its frequency is:
It follows than the period of the wave is:
Therefore, the correct statement is
The period is 1/5 second, and the frequency is 5 Hz.
Learn more about waves, frequency and period:
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Answer:
- path differnce = 2.18*10^-6
- 1538 lines
Explanation:
- The path difference for the waves that produce the pattern of diffraction, is given by the following formula:
(1)
d: separation between slits = 0.50mm = 0.50*10^-3 m
θ: angle of a diffraction = 0.25°
Then, the path difference is:
- The maximum number of bright lines are calculated by using the following formula:
(2)
m: order of the bright
λ: wavelength = 650nm
The maximum bright is calculated for an angle of 90°:
The maxium number of bright lines are twice the previous result, that is, 1538 lines