1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vredina [299]
4 years ago
12

(x^2+x-17)/(x-4) solve this

Mathematics
1 answer:
sergij07 [2.7K]4 years ago
8 0

Answer:

\displaystyle x + 5 + \frac{3}{x - 4}

Step-by-step explanation:

Since the divisor of \displaystyle x - 4is in the form of \displaystyle x - c,we use what is called Synthetic Division. Now, in this formula, −c gives the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:

4| 1 1 −17

↓ 4 20

_________

1 5 3 → \displaystyle x + 5 + \frac{3}{x - 4}

You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [x² + x - 17]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an x, the 5 follows right behind it, and bringing up the rear, \displaystyle \frac{3}{x - 4},giving you the quotient of \displaystyle x + 5 + \frac{3}{x - 4}. However, in this case, since you have a remainder of 3, this gets set over the divisor.

I am joyous to assist you anytime.

You might be interested in
WILL GIVE BRAINLIEST!!
My name is Ann [436]

Answer:

1. x = 1 over 2 or you can simplify by writing x = 0.5

2.x = -1 over 3 or x= -0.3

3.x = -17

4.x = 9

5.x = 7

6.-4 over 9 or x = -0.4

7.x = 1 over 10 or x = 0.1

8.x = 1 over 4 or x = 0.25

9.x = -1

10.x = 13

hope this helps! :-)

6 0
3 years ago
Need help with finding the following with the given equation.
fiasKO [112]
Y=x^2-6x+10. Hopefully that helped
5 0
4 years ago
What is 56,129,482 rounded
JulsSmile [24]
56,129,480 is the answer
6 0
3 years ago
Solve the equation 3(x+1)+2x=1/2(10x-14)
Andrew [12]
3x+3+2x=5x-7
5x+3=5x-7

The 5x cancels each other out

3=-7 which isn’t true
8 0
3 years ago
Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c) The probability that exactly 1 of the next three vehicles passes is 0.189.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let <em>X</em> = number of vehicles that pass the inspection.

The probability of the random variable <em>X</em> is <em>P (X) = 0.70</em>.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

                                    =(0.70)^{3}\\=0.343

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

                                   =1-0.343\\=0.657

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

                         = P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

                              + P (Only 3rd vehicle passes)

                       =(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

                                                       + P (0 vehicles passes)

                                              =0.189+(0.30\times0.30\times0.30)\\=0.216

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let <em>X</em> = all 3 vehicle passes and <em>Y</em> = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0
3 years ago
Other questions:
  • What is the formula for the circumference of a circle in terms of r?
    6·2 answers
  • Ken spent 1/5 of his allowance on a movie, 3/8 on snakes, and 2/7 on games. If of his allowance was $20, how much did Jen have l
    8·1 answer
  • A tortoise is walking in the desert. It walks for 4.8 meters at a speed of 3 meters per minute. For how many minutes does it wal
    6·1 answer
  • Please help! And please explain how you got it so I can understand future problems :3
    7·1 answer
  • If a normal 6 sided die, with each side numbered 1 through 6, is rolled. What is the probability that the number on top is great
    13·1 answer
  • What is the equation of the function that is graphed as line a?
    9·1 answer
  • What property is this: 3 * 1/3 = 1
    12·1 answer
  • 51 is approximately equal to<br> A<br> 7<br> B<br> 5.1<br> с<br> 6<br> D<br> 60
    5·1 answer
  • CAN SOMEONE HELP ME PLEASE ASAP!?
    15·1 answer
  • What is the product of 2 2/3⋅4 1/3?
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!