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Talja [164]
3 years ago
10

What will happen if an object or liquid with a density less than 1.0 g/cm3 is placed into water; do the same for an object or li

quid with a density more than 1.0 g/cm3 ?
Physics
1 answer:
Anna71 [15]3 years ago
3 0
If the object has a lower density than water, it will float.

If the object has a higher density than water, it will sink.
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Suppose a block moves across a rough horizontal surface at constant speed under the action of a horizontal 3-N force. Which stat
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Answer:

Explanation:

A block is moving with constant velocity action the action of 3  N force.

Statement A: False, as the block is moving with constant velocity so net force is zero.

Statement B: False, as the net force is zero.

Statement C: True, the friction force is equal to the applied force.

Statement D: True: The net force is zero so that the block is moving with constant velocity.

Statement E: True, the net force is zero so the acceleration is also zero.

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What is the smallest part of an element
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An atom is the smallest part of an element
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Newton second law of motion relates to force, what, and acceleration
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Newtons second law of motion relates to force, inversely related to its <em><u>mass</u></em><em> </em>and acceleration.

4 0
3 years ago
You are pulling a 80 kg box with a rope. The force you exert on the box is 90 N at 30 degrees from the ground. What would be the
Feliz [49]

Answer:

Coefficient of dynamic friction= md= 0.09931

Explanation:

To determine the coefficient of dynamic friction we must first match the friction force that is permendicular to the normal force of the block and opposite to the drag force, to the component of the drag force in this same direction. This component on the X axis of the drag force will be:

F= 90N × cos(30°) = 77.9423N

This component on the X axis of the drag force must be equal to the dynamic friction force that is equal to the coefficient of dynamic friction by the normal force of the block weight:

F= md × m × g= 77.9423N

m= mass of the block

md= coefficient of dynamic friction

g= gravity acceleration

F= md × 80kg× 9.81 (m/s²)= 77.9423(kg×m/s²)

md= (77.9423(kg×m/s²) / 784.8 (kg×m/s²)) = 0.09931

7 0
3 years ago
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