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solong [7]
3 years ago
14

Two circular plates, each with a radius of 8.22 cm,8.22 cm, have equal and opposite charges of magnitude 3.952 μC.3.952 μC. Calc

ulate the electric field between the two plates. Assume that the separation distance is small in comparison to the diameter of the plates.
Physics
1 answer:
nydimaria [60]3 years ago
7 0

Answer: idk dude ask wpb_cubanBoi23

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10 N

Explanation:

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Assume that the electric field E is equal to zero at a given point. Does it mean that the electric potential V must also be equa
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Answer:

  • No, this doesn't mean the electric potential equals zero.

Explanation:

In electrostatics, the electric field \vec{E} is related to the gradient of the electric potential V with :

\vec{E} (\vec{r}) = - \vec{\nabla} V (\vec{r})

This means that for constant electric potential the electric field must be zero:

V(\vec{r}) = k

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\vec{E} (\vec{r}) = -  (\frac{\partial}{\partial x} , \frac{\partial}{\partial y } , \frac{\partial}{\partial z}) k

\vec{E} (\vec{r}) = -  (\frac{\partial k}{\partial x} , \frac{\partial k}{\partial y } , \frac{\partial k}{\partial z})

\vec{E} (\vec{r}) = -  (0,0,0)

This is not the only case in which we would find an zero electric field, as, any scalar field with gradient zero will give an zero electric field. For example:

V(\vec{r})= (x+2)^2 (y+4)^3 (z+5)^4

give an electric field of zero at point (0,0,0)

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