Answer:
They move at 2.8 m/s and in the opposite direction.
Explanation:
Answer:
151.58 V
Explanation:
From the question,
The work done in a circuit in moving a charge is given as,
W = 1/2QV..................... Equation 1
Where W = Work done in moving the charge, Q = The magnitude of charge, V = potential difference between the plates.
make V the subject of the equation
V = 2W/Q.................. Equation 2
Given: W = 144 J. Q = 1.9 C
Substitute into equation 2
V = 2(144)/1.9
V = 151.58 V
Answer:
Magnitude of induced emf will be 87.5 volt
Direction of induced emf will be clockwise
Explanation:
We have given number of turns in the coil N = 50
Initial area
Time is given dt = 0.1 sec
Magnetic field B = 1.25 T
From Faraday's law of electromagnetic induction
n
So magnitude of induced emf is 87.5 volt
Direction of induced emf will be clockwise
Answer:
The energy loss due to friction is 9465 J.
Explanation:
The given data :-
Mass of roller (m) = 500 kg.
The speed of roller coaster at height 27 m = 5.6 m/s.
Initial height of roller( h ) = 27 m.
The speed of roller coaster at bottom = 22 m/s.
Initial energy of roller at a height 27 m.
E₁ = K.E + P.E
E₁ = = = 7840 + 132435
E₁ = 140,275 J
The energy of roller at a height 2 m.
E₂ = K.E + P.E
E₂ = = = 121000 + 9810
E₂ = 130,810 J
The energy loss due to friction = E₁ - E₂ = 140,275 - 130,810 = 9465 J.
The answer is to your question is force