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3 years ago

Carmen and Judi dock a canoe. 80.0-kg Carmen moves forward at 4.0 m/s as she leaves the canoe. At

Physics

1 answer:

lesya692 [45]3 years ago

6 0

Answer:

They move at 2.8 m/s and in the opposite direction.

Explanation:

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The rate at which speed changes is called

sergiy2304 [10]

Answer:

meters per second

Explanation:

7 0

3 years ago

Read 2 more answers

2. As a pendulum swings, its energy is constantly converted between kinetic

Alex

Answer:

at point F

Explanation:

To know the point in which the pendulum has the greatest potential energy you can assume that the zero reference of the gravitational energy (it is mandatory to define it) is at the bottom of the pendulum.

Then, when the pendulum reaches it maximum height in its motion the gravitational potential energy is

U = mgh

m: mass of the pendulum

g: gravitational constant

The greatest value is obtained when the pendulum reaches y=h

Furthermore, at this point the pendulum stops to come back in ts motion and then the speed is zero, and so, the kinetic energy (K=1/mv^2=0).

A) answer, at point F

6 0

3 years ago

Two particles with charges +6e and -6e are initially very far apart (effectively an infinite distance apart). They are then fixe

JulijaS [17]

Answer:

$\rm EPE_{final}-EPE_{initial}=-1.478\times 10^{-15}\ J.$

Explanation:

Given charges are:

$\rm q_1 = +6e.\\q_2 = -6e.$

The electric potential energy of a charge due to the electric field of another charge is given by

$\rm EPE=\dfrac{kq_1q_2}{r}.$

where,

k = Coulomb's constant, having value = $\rm 9\times 10^9\ Nm^2/C^2.$
r = distance between the charges.

When the charges are infinite distance apart, $\rm r = \infty$ ,

$\rm EPE_{initial} = \dfrac{kq_1q_2}{r}=0\ J.$

When the charges are $\rm 5.61\times 10^{-12}\ m$ apart, $\rm r=5.61\times 10^{-12}\ m$ ,

$\rm EPE_{final}=\dfrac{kq_1q_2}{r}\\=\dfrac{(9\times 10^9)\times (+6e)\times (-6e)}{5.61\times 10^{-12}}\\=-5.775\ e^2\times 10^{22}.$

Here, e is the charge on one electron, such that, $\rm e = -1.6\times 10^{-19}\ C$ .

Therefore,

$\rm EPE_{final}=-5.775\times (-1.6\times 10^{-19})^2\times 10^{22} = -1.478\times 10^{-15}\ J.$

Thus,

$\rm EPE_{final}-EPE_{initial}=-1.478\times 10^{-15}-0=-1.478\times 10^{-15}\ J.$

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3 years ago

In an uncomformity between two layers of rock, how is the lower layer usally described

xenn [34]

The lower layer is thought to be hard and rough

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3 years ago

In the early 1900's ____

Korvikt [17]

Answer:

Henry Ford

Explanation:

he built the first ford

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3 years ago