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Natali5045456 [20]
4 years ago
10

A coil of wire with 50 turns lies in the plane of the page and has an initial area of 0.140 m2. The coil is now stretched to hav

e no area in 0.100 s. What are the magnitude and direction of the average value of the induced emf if the uniform magnetic field points into the page and has a strength of 1.25 T?
Physics
1 answer:
DENIUS [597]4 years ago
7 0

Answer:

Magnitude of induced emf will be 87.5 volt

Direction of induced emf will be clockwise  

Explanation:

We have given number of turns in the coil N = 50

Initial area A=0.140m^2

Time is given dt = 0.1 sec

Magnetic field B = 1.25 T

From Faraday's law of electromagnetic induction

ne=-N\frac{d\Phi }{dt}=-NA\frac{dB}{dt}

e=-50\times 0.140\times \frac{1.25}{0.1}=-87.5volt

So magnitude of induced emf is 87.5 volt

Direction of induced emf will be clockwise

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