i believe the answer is because asphalt conducts heat better
An acid-base reaction or a neutralization reaction is a <u>chemical reaction that occurs between an acid and a base producing a salt and water</u>. The acids and bases can be strong or weak depending on their degree of ionization in water.
Butyric acid is a weak acid and in water it is ionized in the following way, loosing a proton (H+):
HC4H7O2 (aq) ⇆ H+ (aq) + C4H7O2- (aq)
On the other hand, potassium hydroxide is a strong base, so it will be completely ionized in water:
KOH(aq) → K+(aq) + OH-(aq)
Then the <u>net acid-base reaction</u> between butyric acid and KOH is:
HC4H7O2 (aq) + OH- (aq) ⇆ H2O + C4H7O2- (aq)
It is valid to consider only the OH- produced from the ionization of KOH in water since, as mentioned, this molecule is completely ionized. Also, we do not include the K + in the net equation since it is a spectator ion, it does not undergo chemical changes.
The homologous structures and the analogous structures of different species.
Answer: -
Kinetic energy.
Explanation: -
Solids have the least kinetic energy and the highest intermolecular force of attraction among the three states of matter.
When heat energy is supplied to the solid, the kinetic energy of the solid particles increases. At some point, the kinetic energy becomes comparable to the intermolecular force of attraction. At that point solids change into liquids.
When further heat energy is given, at certain point the kinetic energy becomes far greater than the intermolecular forces of attraction. At that point it becomes gas.
Answer:
12 liters of oxygen are released from the decomposition of the peroxide.
Explanation:
The hydrogen peroxide is decomposed by this reaction:
2 H₂O₂ (l) → 2 H₂O (l) + O₂ (g)
Molar mass H₂O₂ = 34 g/m
Moles of peroxide: 36.5 g / 34 g/m = 1.07 moles
Ratio is 2:1, so 2 moles of peroxide will be decomposed in 1 mol of oxygen (exactly the half)
1.07 moles of peroxide will be decomposed in the half of moles, 0.54 moles
Let's apply the Ideal Gases law Equation to solve the volume
1 atm . V = 0.54 mol . 0.082 .273K
V = (0.54 mol . 0.082 .273K) / 1 atm → 12L
