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timurjin [86]
3 years ago
10

Are HF CH4 and CO2 acids or bases>

Chemistry
1 answer:
Vlad [161]3 years ago
4 0
Huh I do not understand this
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When you take 10 grams of salt, and dissolve it in 25 grams of hot water what is the solubility
AURORKA [14]

Answer:

When salt is mixed with water, the salt dissolves because the covalent bonds of water are stronger than the ionic bonds in the salt molecules. ... Water molecules pull the sodium and chloride ions apart, breaking the ionic bond that held them together.

Explanation:

4 0
2 years ago
If we react 30 grams of ethane (C2H6 ) with 320 grams of oxygen, how many grams of carbon dioxide would we make
V125BC [204]

The mass of carbon dioxide that would be made by reacting 30 grams C2H6 with 320 grams O2 will be 80 grams

From the balanced equation of the reaction:

2C_2H_6+7O_2---4CO_2+6H_2O

The mole ratio of C2H6 to O2 is 2:7.

  • Mole of 30 grams C2H6 = mass/molar mass

                                        = 30/30

                                       = 1 mole

  • Mole of 320 grams O2 = 320/32

                                       = 10 moles

Thus, C2H6 is the limiting reactant.

Mole ratio of C2H6 to CO2 according to the equation = 1:2

Since the mole of C2H6 is 1, the equivalent mole of CO2 would, therefore, be 2.

Mass of 2 moles CO2 = mole x molar mass

                                    = 2 x 44

                                      = 88 grams

More on stoichiometric calculations can be found here: brainly.com/question/8062886?referrer=searchResults

6 0
3 years ago
Waves move out through the ground from the source of an<br> earthquake.<br> True<br> ► False
goblinko [34]

I believe the answer would be true

3 0
3 years ago
Why do all the elements in Group 16 share similar properties?
geniusboy [140]
D. They all have the same number of valence electrons.
5 0
3 years ago
A balloon has a volume of 3.0 L at room temperature (27oC). At what temperature would the balloon have a volume of 4.0L?
diamong [38]

Answer: 400K

Explanation:

Given that,

Original volume of balloon V1 = 3.0L

Original temperature of balloonT1 = 27°C

Convert the temperature in Celsius to Kelvin

(27°C + 273 = 300K)

New volume of balloon V2 = 4.0L

New temperature of balloon T2 = ?

Since volume and temperature are given while pressure is constant, apply the formula for Charle's law

V1/T1 = V2/T2

3.0L/300K = 4.0L/T2

To get the value of T2, cross multiply

3.0L x T2 = 4.0L x 300K

3.0LT2 = 1200LK

Divide both sides by 3.0L

3.0LT2/3.0L = 1200LK/3.0L

T2 = 400K

Thus, at a temperature of 400 Kelvin, the balloon would have a volume of 4.0L.

6 0
3 years ago
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