Yes that would be ok, explain how it works though.
Answer:
It's C
Protons repel the neutrons.
Explanation:
An atom is unstable (radioactive) if these forces are unbalanced; if the nucleus has an excess of internal energy. The instability of an atom's nucleus may result from an excess of either neutrons or protons.
Answer:
The specific heat capacity of silver is 0.24 j/g.°C.
Explanation:
Given data:
Mass of sample = 55.00 g
increase of temperature ΔT= 15.0 °C
Heat absorbed = 193.9 J
Specific heat capacity of silver = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance.
ΔT = change in temperature
Now we will put the values in formula.
193.9 J = 55.00 g × c ×15.0 °C
193.9 J = 825 g.°C × c
c = 193.9 J / 825 g.°C
c= 0.24 /g.°C
The specific heat capacity of silver is 0.24 j/g.°C.
Calcium oxide CaO = 40+16 = 56
Calcium hydroxide Ca(OH)_2 = 40+16+16+1+1 = 74
The ratio 56:74 is equal to 14:x with x being the unknown mass.
56/14 = 4
74/4 = 18.5
So the answer is 18.5g assuming the water is in excess
Answer:
Combustion reaction
2C2H6+7O2 → 4O2+6H2O
Explanation:
In a combustion reaction with a hydrocarbon in the reactant side you will always have O2 as another reactant. As you will always have CO2 and H2O as the products.
Knowing that much you can set up your reaction equation..
C2H6+O2→ CO2+H2O
Now the balancing can begin. Balancing hydrocarbon combustion reactions can be tricky, but if with practice they can be really fun and very rewarding.
Start with the C atoms first and move to the H atoms next. It's easier to leave the O2 to the last, it has a way to alter the equation.
Initially, you would arrive at this, before the O2 has been balanced:
C2H6+O2→2CO2+3H2O
But, as you can see, you have an odd amount of O2 on the product side. In this case, you have to find the common factor of the amount of O on the product side and 2, Because of the O2 diatom. Therefore, 14 would be the lowest common factor of 2 and 7.
I hope it helped you!
