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Darina [25.2K]
2 years ago
9

The aria ""batter my heart"" from doctor atomic has musical influences from which era?

Chemistry
1 answer:
irga5000 [103]2 years ago
5 0

The aria ""batter my heart"" from doctor atomic has musical influences from the era of Renaissance.

<h3>Why is batter my heart attributed to  to Renaissance era?</h3>

The Renaissance era can be regarded as the era around 14th century and batter my heart was produced around the 13/14th century.

The batter my heart was among the Sicilian school of court poets, that was very famous which  emphasizing the importance of the heart.

Learn more about  batter my heart at: brainly.com/question/10025363

#SPJ12

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Answer : It is a conclusion.

Explanation:

Conclusion: It is a judgement or decision which can be attained by reasoning.

From the observation table given we can conclude that :

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  • Copper took less time of 15 seconds to melt the small piece of wax in comparison to other metal pots which means that it is a good conductor of heat in comparison to other. Hence, copper pot would be better for cooking food quickly.

After analyzing the observations and results in an experiment conclusion was made that copper pots are best for cooking foods.

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In the Haber process for ammonia synthesis, K " 0.036 for N 2 (g) ! 3 H 2 (g) ∆ 2 NH 3 (g) at 500. K. If a 2.0-L reactor is char
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Answer : The partial pressure of N_2,H_2\text{ and }NH_3 at equilibrium are, 1.133, 2.009, 0.574 bar respectively. The total pressure at equilibrium is, 3.716 bar

Solution :  Given,

Initial pressure of N_2 = 1.42 bar

Initial pressure of H_2 = 2.87 bar

K_p = 0.036

The given equilibrium reaction is,

                              N_2(g)+H_2(g)\rightleftharpoons 2NH_3(g)

Initially                   1.42      2.87             0

At equilibrium    (1.42-x)  (2.87-3x)     2x

The expression of K_p will be,

K_p=\frac{(p_{NH_3})^2}{(p_{N_2})(p_{H_2})^3}

Now put all the values of partial pressure, we get

0.036=\frac{(2x)^2}{(1.42-x)\times (2.87-3x)^3}

By solving the term x, we get

x=0.287\text{ and }3.889

From the values of 'x' we conclude that, x = 3.889 can not more than initial partial pressures. So, the value of 'x' which is equal to 3.889 is not consider.

Thus, the partial pressure of NH_3 at equilibrium = 2x = 2 × 0.287 = 0.574 bar

The partial pressure of N_2 at equilibrium = (1.42-x) = (1.42-0.287) = 1.133 bar

The partial pressure of H_2 at equilibrium = (2.87-3x) = [2.87-3(0.287)] = 2.009 bar

The total pressure at equilibrium = Partial pressure of N_2 + Partial pressure of H_2 + Partial pressure of NH_3

The total pressure at equilibrium = 1.133 + 2.009 + 0.574 = 3.716 bar

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