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3 years ago

Would the boiling point of water at 0.5 atm be lower, the same, or higher than the

Chemistry

1 answer:

dsp733 years ago

3 0

Answer:

Lower.

Explanation:

When you lower the pressure of water, it will usually decrease the boiling point. So, the higher you are on Earth, the lower the boiling point of H2O becomes.

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Answer the following questions:

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Answer:

the melting point is the factor what what degrees fahrenheit a metal or other solid substance melts. the significance of knowing the melting point can help you determine how long or how hot to burn the tested object while at the same time determining the safety requirements.

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2 years ago

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3 years ago

A scientist is studying a shock wave from an earthquake. What kind of wave is being studying?

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Answer:

A scientist is studying a shock wave from an earthquake, he is studying mechanical wave.

Explanation:

The shock waves are experienced during earthquake. At the area of increased pressure shock wave are created as the object in that places moves faster as compared to the speed of sound. Shock wave are type of mechanical wave. For its transfer it requires a medium. An electromagnetic wave can travel of its own without any medium, under electromagnetic wave gamma ray and radio wave comes. they are transverse wave.

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4 years ago

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An ethylene glycol solution contains 21.4 g of ethylene glycol (C2H6O2) in 97.6 mL of water. (Assume a density of 1.00 g/mL for

8090 [49]

Answer: The freezing point and boiling point of the solution are $-6.6^0C$ and $101.8^0C$ respectively.

Explanation:

Depression in freezing point:

$T_f^0-T^f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_f$ = freezing point of solution = ?

$T^o_f$ = freezing point of water = $0^0C$

$k_f$ = freezing point constant of water = $1.86^0C/m$

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

$w_2$ = mass of solute (ethylene glycol) = 21.4 g

$w_1$ = mass of solvent (water) = $density\times volume=1.00g/ml\times 97.6ml=97.6g$

$M_2$ = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

$(0-T_f)^0C=1\times (1.86^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}$

$T_f=-6.6^0C$

Therefore,the freezing point of the solution is $-6.6^0C$

Elevation in boiling point :

$T_b-T^b^0=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_b$ = boiling point of solution = ?

$T^o_b$ = boiling point of water = $100^0C$

$k_b$ = boiling point constant of water = $0.52^0C/m$

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

$w_2$ = mass of solute (ethylene glycol) = 21.4 g

$w_1$ = mass of solvent (water) = $density\times volume=1.00g/ml\times 97.6ml=97.6g$

$M_2$ = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

$(T_b-100)^0C=1\times (0.52^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}$

$T_b=101.8^0C$

Thus the boiling point of the solution is $101.8^0C$

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4 years ago

Which statement defines reduction potential when considering a pair of half-cell reactions?

Ivahew [28]

The half reaction with the the greater SRP has a greater tendency to gain electrons is the definition of reduction potential when considering a pair of half cell reactions.This reduction potential is measured against hydrogen electrode which is standard electrode.

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3 years ago