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Travka [436]
3 years ago
15

How are quantum numbers related to atomic orbitals?

Chemistry
1 answer:
sdas [7]3 years ago
3 0
When considering atomic orbitals the only important information they really wanted to know is the size of the orbit, which was described by using quantum numbers.
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Do ionic or covalent substances tend to produce more ions in solution? ...?
sasho [114]
The answer for the given question above is IONIC. <span>Ionic substances form giant ionic </span>lattices<span> containing oppositely charged ions. They have high melting and boiling points, and </span>conduct<span> electricity when melted or dissolved in water.</span>
8 0
3 years ago
Read 2 more answers
Be sure to answer all parts.The combustion of a 40.0−g gaseous mixture of H2 and CH4 releases 3766 kJ of heat. Calculate the amo
Svetach [21]

Answer:H2=11.4g

CH4=28.6g

Explanation:The complete combustion of the two gases can be represented by a balanced reaction below

1. CH4 +2O2___CO2+2H2O

2.2H2+O2___2H2O

Combining the two we have CH4 +2H2+3O2___

CO2+4H2O

Since the mixture contains 40gof CH4 and 2, therefore 20g of CH4 and 8g of H2 combines.

Calculated from their molecular Mass i.e CH4 12+4×2)=20 and 2H2= 2×2×2=8g

Mass of CH4=20/28×40=28.6g

2H2=8/28×40=11.4g

7 0
3 years ago
Can anyone help me please?
Nady [450]

10. Is A

11. Is D

12. Is D

13. Is B

5 0
3 years ago
Someone please do this!!!
Lilit [14]

Answer:

1) Fe = 69.9%

O = 31.1%

2) H = 5.19%

O = 16.5%

N = 28.9%

C = 49.5%

Explanation:

One easy way to do percent compositions is to assume you have 100g of a substance.

1) Lets say we have 100g of Fe2O3.

The total molar mass would be:

= 55.845*2+15.999*3 = 159.687

The molar mass of the Fe2 alone is:

=55.845*2 = 111.69

Thus, the grams of Fe2(out of a 100) could be calculated by multiplying 100g * the molar mass ratio of Fe2 to the whole:

= 100g *\frac{111.69}{159.687} = 69.9431

Which is approximately 69.9%.

We can find the amount of O3 by simply subtracting, as the rest of the compound is made of O3. Thus, the % composition of O3 is 31.1%

You can then do this same process to the next question, getting us the following:

H = 5.19%

O = 16.5%

N = 28.9%

C = 49.5%

4 0
2 years ago
What is the effect of molecular weight on melting and boiling point of alkanes??​
Readme [11.4K]

Answer:

Their melting and boiling points of alkanes are relatively low. The higher the molecular weight (the greater the number of carbons), the higher the boiling point.

8 0
3 years ago
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