Answer:
24.5
Explanation:
15/6.3 => 2.38 half lives passed.
.5^2.38 => 0.19198 decimal representation of the percentage that is left over after 2.38 half lives have passed.
0.19198 *128 = 24.5 mg of the material remaining.
K₂CrO₄(aq) + Ba(NO₃)₂(aq) = BaCrO₄(s) + 2KNO₃(aq)
2K⁺ + CrO₄²⁻ + Ba²⁺ + 2NO₃⁻ = BaCrO₄ + 2K⁺ + 2NO₃⁻
spectator ions: K⁺, NO₃⁻
<span>it is limited to situations that involve aqueous solutions of specific compounds
I hope this helps</span>
