Answer:
Magnesium bromide, MgBr2, and water, H2O.
Explanation:
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In this case, since HBr is an acid and Mg(OH)2 is a base, an acid-base reaction is undergone, by which a salt and water are produced as neutralization products:
However, it need to be balanced since two bromine atoms are produced, therefore we write:
Thus, the products are magnesium bromide, MgBr2, and water, H2O.
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1 atm = 101,325 Pa = 101.325 kPa
Pa is Pascals, and kPa is kilopascals.
0.750 atm * 101.325 kPa/1 atm = 75.99 kPa = 76.0 kPa
The answer needs to be in 3 significant figures, and therefore 0.750 atm = 76.0 kPa.
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Molar mass :
NaBr = 103 g/mol
Pb(NO3)2 = 331.20 g/mol
<span><span /><span>Balanced chemical equation :
</span></span>2 NaBr + 1 Pb(NO3)2 = 2 NaNO3 + 1 PbBr<span>2
</span><span>
2*103 g NaBr ------------> 1 * 331.20 g Pb(NO3)2
g NaBr -------------------> 311 g Pb(NO3)2
331.20 g = 2*103*311
331.20 g = 64066
mass ( NaBr ) = 64066 / 331.20
mass ( naBr) = 193,43 g of NaBr
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When Heat is added to it.