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Afina-wow [57]
3 years ago
5

What happens to the density of water as its salinity increases? Please select the best answer from the choices provided

Chemistry
2 answers:
umka2103 [35]3 years ago
8 0
█ Explanation █  

<span>When the density of water as its salinity increases, its density increases, too.

Answer: Letter A

</span><span>Hope that helps! ★ <span>If you have further questions about this question or need more help, feel free to comment below or leave me a PM. -UnicornFudge aka Nadia </span></span>
hodyreva [135]3 years ago
8 0
The answer is A. the density increases
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The atomic number of an atom is the number of ______ in the atom's nucleus. *
nasty-shy [4]

the answer would be protons

8 0
2 years ago
What is the mass of 1.72 moles of BaSO4?
Fiesta28 [93]

Answer: 401.4g

Explanation:

The mass can be calculated by using the following mathematical expression for Moles ,which is:

Moles = Mass / Molar Mass

From the question given, Moles = 1.72, Molar mass of BaSO4 = 233.38g/mol, Mass =?

Making 'Mass' the subject of formula, we get:

Mass = Molar mass x Moles

= 233.38 x 1.72 = 401.4g

3 0
3 years ago
1. How many moles of iron is needed to react with sulfur in order to produce 8.6 moles
AleksAgata [21]

Answer:

17.2 moles of Iron are required

Explanation:

Based on the chemical reaction:

2Fe + 3S → Fe₂S₃

<em>2 moles of Fe react with 3 moles of S to produce 1 mole of Iron (III) sulfide</em>

<em />

Assuming and excess of sulfur, if we want to obtain 8.6 moles of Fe₂S₃ are required:

8.6 moles Fe₂S₃ * (2 moles Fe / 1mol Fe₂S₃) =

<h3>17.2 moles of Iron are required</h3>
7 0
3 years ago
QUESTION 1
Lisa [10]
B obviously not a or c so if it aint b its D
3 0
3 years ago
Read 2 more answers
Which of the following changes to a pipe would increase the conductance by a factor of 12?
ivanzaharov [21]

C. Tripling the length and reducing the radius by a factor of 2 is the change to a pipe would increase the conductance by a factor of 12.

<u>Explanation:</u>

As we know that the resistance is directly proportional to the length of the pipe and it is inversely proportional to the cross sectional area of the pipe.

So it is represented as,

R∝ l /A [ area is radius square]

So k is the proportionality constant used.

R = kl/A

Conductance is the inverse of resistance, so it is given as,

C= 1/R.

R₁ = kl₁ / A₁

R₂ = kl₂/A₂

R₂/R₁ = 1/12 [∵ conductance is the inverse of resistance]

        = l₂A₁ / l₁A₂

If we chose l₁/l₂= 3 and A₂/A₁= 4 So R₂/R₁= 1/3×4 = 1/12

So tripling the length and reducing the radius by a factor of 2 would increase the conductance by a factor of 12.

6 0
3 years ago
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