Answer:
Cellular respiration.
Explanation:
Through the process of cellular respiration, the energy in food is converted into energy that can be used by the body's cells. During cellular respiration, glucose and oxygen are converted into carbon dioxide and water, and the energy is transferred to ATP.
How does the law of conservation of mass apply to this reaction: C2H4 + O2 → H2O + CO2?
Answer:
13500 N
Explanation:
According to newtons second law of motion
mass m =1500 Kg
a = 9m/s^2
Force F = mass m × acceleration a
F = 1500×9= 13500 N
Answer:
The molality of isoborneol in camphor is 0.53 mol/kg.
Explanation:
Melting point of pure camphor= T =179°C
Melting point of sample =
= 165°C
Depression in freezing point = 

Depression in freezing point is also given by formula:

= The freezing point depression constant
m = molality of the sample
i = van't Hoff factor
We have:
= 40°C kg/mol
i = 1 ( organic compounds)



The molality of isoborneol in camphor is 0.53 mol/kg.
According to Newton's first law of motion, it takes an unbalanced force to move an object at rest.
I hope this helps :)