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3 years ago

What are the 5 steps of a cloud forming and how would I draw it

Chemistry

1 answer:

zhannawk [14.2K]3 years ago

3 0

Warm air rises and cools2the relative humidity of the air increases3air eventually becomes saturated4water vapor condenses on smoke, dust, salt, and other small particals5<span>millions of tiny water drops of liquid water collect to form a cloud</span>

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A force of 20 N acts upon 5 kg block caculate the accerleration of the object

Vedmedyk [2.9K]

Answer:

$\boxed{\text{4 m $\cdot$ s$^{-2}$}}$

Explanation:

F = ma

$a = \dfrac{F}{m} = \dfrac{\text{20 N}}{\text{5 kg}} \times \dfrac{\text{1 kg$\cdot$ m $\cdot$ s$^{-2}$}}{\text{1 N}} = \text{4 m $\cdot$ s$^{-2}$}\\\\\text{The acceleration of the object is } \boxed{\textbf{4 m $\cdot$ s$^{\mathbf{-2}}$}}$

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3 years ago

the decomposition of calcium carbonate to calcium oxide and carbon dioxide only takes place at very high temperatures, making th

USPshnik [31]

So calculate the H for the other two reactions a room temperature and combine the reactions to calculate the H of the decomposition of calcium carbonate using the Hess's Law

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2 years ago

HELP ILL GIVE U FREE POINTS AND BRAINLEST !! Observe the plate boundary shown here. What type of plate boundary is this? Many ge

Studentka2010 [4]

The answer is B.
You can rule C out because divergent means moving away. Rule out A because there is an oceanic and continental plate, not 2 of the same type. Rule D out for the same reason.

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2 years ago

Read 2 more answers

Which of the following hazards does not apply for methanol?

AleksAgata [21]

Answer: the answer is C oxidizing

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2 years ago

Estimate the ph of the resulting solution prepared by mixing 1.0 mole of solid disodium phosphate (na2hpo4) and 1.25 mole of hyd

GenaCL600 [577]

The HCl added = 1.25 moles

and the moles of Na2HPO4 = 1 mole

Now when acid is added in the given solution of Na2HPO4

One mole of H+ will react with one mole of Na2HPO4 to given one mole of NaH2PO4

Na2HPO4 + H+ ---> NaH2PO4

Now this one mole formed NaH2PO4 will further react with 0.25 moles of H+ left to form 0.25 moles of H3PO4 and 0.75 moles of NaH2PO4 will remain in the solution

So this will result into formation of a buffer of phosphoric acid and NaH2PO4

NaH2PO4 + H+ ---> H3PO4

pKa of H3PO4 = 2.1

so pH = pKa + log [salt] / [acid] = 2.1 + log [0.75 / 0.25] = 2.58

so the pH will be in between 2.1 to 7.2

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3 years ago