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tigry1 [53]
3 years ago
11

How can we find the volume of this fish tank? Please I needed but Good

Chemistry
2 answers:
Lana71 [14]3 years ago
5 0

Answer:

The correct answer is find the number of 1 foot cubes that fill the fish tanks.

Explanation:

Volume is defined as amount of space occupied by an object.

Number of 1 foot cubes lying on the length of fish tank ,l= 5 feet

Number of 1 foot cubes lying on the width of fish tank,w = 3 feet

Number of 1 foot cubes lying on the height of fish tank ,h= 3 feet

Volume of the cuboid fish tank will be :

l\times b\times h=5 feet\times 3 feet \times 3feet=45 feet^3

The volume of fish tanks id 45 cubic feet.

lawyer [7]3 years ago
3 0
Volume well in the picture the fish tank seems to be a rectangle, so you would do V=length x width x height. So V=5x3x3=45
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Calculate the pH of a solution prepared by dissolving 0.370 mol of formic acid (HCO2H) and 0.230 mol of sodium formate (NaCO2H)
Veronika [31]

The question is incomplete, here is the complete question:

Calculate the pH of a solution prepared by dissolving 0.370 mol of formic acid (HCO₂H) and 0.230 mol of sodium formate (NaCO₂H) in water sufficient to yield 1.00 L of solution. The Ka of formic acid is 1.77 × 10⁻⁴

a) 2.099

b) 10.463

c) 3.546

d) 2.307

e) 3.952

<u>Answer:</u> The pH of the solution is 3.546

<u>Explanation:</u>

We are given:

Moles of formic acid = 0.370 moles

Moles of sodium formate = 0.230 moles

Volume of solution = 1 L

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:  

pH=pK_a+\log(\frac{[salt]}{[acid]})

pH=pK_a+\log(\frac{[HCOONa]}{[HCOOH]})

pK_a = negative logarithm of acid dissociation constant of formic acid = 3.75

[HCOONa]=\frac{0.230}{1}  

[HCOOH]=\frac{0.370}{1}

pH = ?  

Putting values in above equation, we get:  

pH=3.75+\log(\frac{0.23/1}{0.37/1})\\\\pH=3.54

Hence, the pH of the solution is 3.546

5 0
3 years ago
Convert 2.39 x 1022 molecules of water into moles of water
torisob [31]

Answer:

0.0397\ \text{mol}

Explanation:

Number of molecules of water = 2.39\times 10^{22}

N_A = Avogadro's number = 6.022\times 10^{23}\ \text{mol}^{-1}

Number of moles is given by

\dfrac{2.39\times 10^{22}}{6.022\times 10^{23}}

=0.0397\ \text{mol}

The number of moles of water is 0.0397\ \text{mol}.

6 0
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A cylinder containing carbon dioxide of volume 20 L at 2.0 atm was connected to another cylinder of certain volume at constant t
den301095 [7]

Answer:

The volume of the second cylinder is 80 liters

Explanation:

We use the Boyle-Mariotte formula, according to which the pressure and volume of a gas are inversely related, keeping the temperature constant: P1 x V1 = P2xV2. We convert the pressure in mmHg to atm:

760 mmHg-----1 atm

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P1xV1=P2xV2

2 atmx20 L= 0,5atm x V2 V2=(2 atmx20 L)/0,5atm=80L

8 0
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