Here is the full question:
Cu(s) + 4HNO3(aq) -> Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l)
1.000 g copper wire is reacted with 10 mL of concentrated nitric acid (16M). If 0.953 g of copper was actually recovered at the end of the entire experiment, what would be the percent yield?
Answer:
95.30 %
Explanation:
equation for the reaction is given as:
Cu(s) + 4HNO3(aq) -> Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l)
1.00 g of Cu = 
= 0.01574 mol of Cu
10 mL of 16 M HNO3 = 
= 0.16 mol of HNO3
However, from both variables; we can arrive at a conclusion that Cu is the limiting reagent.
therefore % yield = = 4.70 %
Percentage yield = 
Percentage yield = 
%
Percentage yield = 0.953 × 100%
Percentage yield = 95.30 %
Atoms are smaller than molecules, and they are also the smallest building blocks of matter. Atoms make up molecules when two or more atoms bond.
Answer:
It is mostly water (up to 95% by volume), and contains dissolved proteins (6–8%) (e.g. serum albumins, globulins, and fibrinogen), glucose, clotting factors, electrolytes (Na+, Ca2+, Mg2+, HCO3−, Cl−, etc.), hormones, carbon dioxide (plasma being the main medium for excretory product transportation) and oxygen.
hope this helps :)
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Answer : The molarity of solution is, 1.73 mole/L
Explanation :
The relation between the molarity, molality and the density of the solution is,
where,
![d=M[\frac{1}{m}+\frac{M_b}{1000}]](https://tex.z-dn.net/?f=d%3DM%5B%5Cfrac%7B1%7D%7Bm%7D%2B%5Cfrac%7BM_b%7D%7B1000%7D%5D)
d = density of solution = 
m = molality of solution = 2.41 mol/kg
M = molarity of solution = ?
= molar mass of solute (toluene) = 92 g/mole
Now put all the given values in the above formula, we get the molality of the solution.
![0.876g/ml=M\times [\frac{1}{2.41mol/kg}+\frac{92g/mole}{1000}]](https://tex.z-dn.net/?f=0.876g%2Fml%3DM%5Ctimes%20%5B%5Cfrac%7B1%7D%7B2.41mol%2Fkg%7D%2B%5Cfrac%7B92g%2Fmole%7D%7B1000%7D%5D)
Therefore, the molarity of solution is, 1.73 mole/L
