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3 years ago

What is the solution to this question -14x=70

Mathematics

2 answers:

riadik2000 [5.3K]3 years ago

8 0

X will equal -5
Hope I've helped

Sloan [31]3 years ago

6 0

-14x=70

Dive both sides by -14, and you end up with:

x=-5

hope this helps!

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Andrew received a raise from $14,580.00 per year to $25,317.40 per year. He received

skelet666 [1.2K]

Answer:

Step-by-step explanation:

$25,317.40 is about 57.5% higher than $14,580.00

57% doesn't fit the answers you provided, so either something is missing in the question, or the numbers may be messed up, or the answer is just 57.5%.

A 2% raise would be $14,871.60 per year.

A 3% raise would be $15,017.40 per year.

A 7.4% raise would be $15,658.92 per year.

A 29% raise would be $18,808.20 per year.

I hope this helps

7 0

3 years ago

Find the Least Common Denominator of the fractions: 6/7 and 2/3

serg [7]

Answer:

The least common denominator is 21

Step-by-step explanation:

3 & 7 equal 21 which is the least common factor that it equals

7 0

3 years ago

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Yuki´s guppies have begun to have babies . She started with 5 guppies. One week later,yuki counted twice as many guppies in the

Sati [7]

Answer:6 weeks

Step-by-step explanation: 5, 10, 20, 40, 80, 160

8 0

3 years ago

(10 points) Consider the initial value problem y′+3y=9t,y(0)=7. Take the Laplace transform of both sides of the given differenti

Rashid [163]

Answer:

The solution

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3 t}$

Step-by-step explanation:

Explanation:-

Consider the initial value problem y′+3 y=9 t,y(0)=7

Step(i):-

Given differential problem

y′+3 y=9 t

Take the Laplace transform of both sides of the differential equation

L( y′+3 y) = L(9 t)

Using Formula Transform of derivatives

L(y¹(t)) = s y⁻(s)-y(0)

By using Laplace transform formula

$L(t) = \frac{1}{S^{2} }$

Step(ii):-

Given

L( y′(t)) + 3 L (y(t)) = 9 L( t)

$s y^{-} (s) - y(0) + 3y^{-}(s) = \frac{9}{s^{2} }$

$s y^{-} (s) - 7 + 3y^{-}(s) = \frac{9}{s^{2} }$

Taking common y⁻(s) and simplification, we get

$( s + 3)y^{-}(s) = \frac{9}{s^{2} }+7$

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

Step(iii):-

By using partial fractions , we get

$\frac{9}{s^{2} (s+3} = \frac{A}{s} + \frac{B}{s^{2} } + \frac{C}{s+3}$

$\frac{9}{s^{2} (s+3} = \frac{As(s+3)+B(s+3)+Cs^{2} }{s^{2} (s+3)}$

On simplification we get

9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Put s =0 in equation(i)

9 = B(0+3)

B = 9/3 = 3

Put s = -3 in equation(i)

9 = C(-3)²

C = 1

Given Equation 9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Comparing 'S²' coefficient on both sides, we get

9 = A s²+3 A s +B(s)+3 B +C(s²)

0 = A + C

put C=1 , becomes A = -1

$\frac{9}{s^{2} (s+3} = \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}$

Step(iv):-

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

$y^{-}(s) =9( \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}) + \frac{7}{s+3}$

Applying inverse Laplace transform on both sides

$L^{-1} (y^{-}(s) ) =L^{-1} (9( \frac{-1}{s}) + L^{-1} (\frac{3}{s^{2} }) + L^{-1} (\frac{1}{s+3}) )+ L^{-1} (\frac{7}{s+3})$

By using inverse Laplace transform

$L^{-1} (\frac{1}{s} ) =1$

$L^{-1} (\frac{1}{s^{2} } ) = \frac{t}{1!}$

$L^{-1} (\frac{1}{s+a} ) =e^{-at}$

Final answer:-

Now the solution , we get

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3t}$

5 0

3 years ago

Solve −4 = −(−k − 86)+10

kvasek [131]

K= 100

You use distributive property

Step 1: −(−k)−1(−86)+10=−4

Step 2: k−1(−86)+10=−4

Step 3: k+86+10=−4

Step 4: k+96=−4

Step 5: k=−96−4

Step 6: Subtract 4 from −96 to get −100.

3 0

3 years ago

Read 2 more answers