637,980 Joules is needed to raise the temperature of 2.50 kg of this oil from 23 ∘C to 191 ∘C.
<h3>What is specific heat?</h3>
The heat in calories required to raise the temperature of one gram of a substance one degree Celsius.
Q = cmΔT
where
Q = heat energy needed for that material to get desired temperature change (in Joules)
M = mass (in grams) so you have to convert from kilograms.
c = specific heat constant for the material being heated
ΔT = change in temperature
Q = (1.75)(2.17 x 1000)(191 - 23)
Q = (1.75)(2170)(168)
Q = 637,980 Joules
Hence, 637,980 Joules is needed to raise the temperature of 2.50 kg of this oil from 23 ∘C to 191 ∘C.
Learn more about the specific heat capacity here:
brainly.com/question/9560546
#SPJ1
Answer:
star 3
Explanation:
the color determines the fusion in between
The molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.
<u>Explanation:</u>
Molality is the measure of how much of amount of solute is dissolved in the solvent. So it is calculated as the ratio of moles of solute to the grams of solvent.
As in this case, the solute is NaCl and solvent is unknown. So the moles of solute is given as 1.34 moles and the mass of solvent is given as 2.47 kg.
Hence,
Thus, the molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.
Answer:
= a) chirality
Explanation:
Because chiral molecules has four different atoms bonded to the central atom, hence they rotate plane polarized light and produces non-superimposable mirror images
Answer : The specific heat of fools gold is .
Solution : Given,
Molar specific heat of fools gold =
Formula weight of fools gold = 119.98 g/mole
Formula used :
Molar specific heat substance = Specific heat of substance × Formula weight of substance
Now we have to calculate the specific heat of fools gold.
Now put all the given values in this formula, we get
Therefore, the specific heat of fools gold is .