Consider a U-tube whose arms are open to the atmosphere. Now water is poured into the U-tube from one arm, and light oil (???? =
790 kg/m3) from the other. One arm contains 70-cm-high water, while the other arm contains both fluids with an oil-to-water height ratio of 6. Determine the height of each fluid in that arm.
1 answer:
Answer:
Oil high= 73.14cm
Water high= 12.19cm
Explanation:
See the attached images.
The first important concept is that in an open tube at both ends the atmospheric pressure balances itself.
The pressure on both sides of the tube is the same in the equilibrium. The pressure of each fluid depends on its height and density.
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Answer:
The answer to the question is
The rate constant for the reaction is 1.056×10⁻³ M/s
Explanation:
To solve the question, e note that
For a zero order reaction, the rate law is given by
[A] = -k×t + [A]₀
This can be represented by the linear equation y = mx + c
Such that y = [A], m which is the gradient is = -k, and the intercept c = [A]₀
Therefore the rate constant k which is the gradient is given by
Gradient = where [A]₁ = 8.10×10⁻² M and [A]₂ = 1.80×10⁻³ M
= = -0.001056 M/s = -1.056×10⁻³ M/s
Threfore k = 1.056×10⁻³ M/s