Consider a U-tube whose arms are open to the atmosphere. Now water is poured into the U-tube from one arm, and light oil (???? =
790 kg/m3) from the other. One arm contains 70-cm-high water, while the other arm contains both fluids with an oil-to-water height ratio of 6. Determine the height of each fluid in that arm.
1 answer:
Answer:
Oil high= 73.14cm
Water high= 12.19cm
Explanation:
See the attached images.
The first important concept is that in an open tube at both ends the atmospheric pressure balances itself.
The pressure on both sides of the tube is the same in the equilibrium. The pressure of each fluid depends on its height and density.
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Answer:
T = 525K
Explanation:
The temperature of the two-level system can be calculated using the equation of Boltzmann distribution:
(1)
<em>where Ni: is the number of particles in the state i, N: is the total number of particles, ΔE: is the energy separation between the two levels, k: is the Boltzmann constant, and T: is the temperature of the system </em>
The energy between the two levels (ΔE) is:
<em>where h: is the Planck constant, c: is the speed of light and k: is the wavenumber</em>
Solving the equation (1) for T:
<em>With Ni = N/3 and k = 1.38x10⁻²³ J/K, </em><em>the temperature of the two-level system is:</em><em> </em>
I hope it helps you!