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mart [117]
3 years ago
8

What mechanisms do astronomers believe is responsible for making the Sun's outer atmosphere so much hotter than its photosphere?

Physics
1 answer:
IrinaVladis [17]3 years ago
5 0

Answer:

magneto hydrodynamic( MHD) waves

Explanation:

The surface of the Sun transmits magneto hydrodynamic( MHD) waves to its atmosphere. These waves carry energy from the sun's surface to its atmosphere ( Corona) and heat up the atmosphere to such extent that its temperature rises to many time than that of the surface temperature of the Sun.

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The two structural members, one of which is in tension and the other in compression, exert the indicated forces on joint o. dete
melisa1 [442]
We're going to remedy it with the parallelogram law. 
\alpha = one hundred eighty - 30 - 70 = eighty degrees
R = sqrt(2^2 + 3^2 - 2(2)(three) cos(80)
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sin\beta/3 = sin(eighty)/three.304 = 63.4 stages

3.3 kN 
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4 0
4 years ago
1. When two atoms of the same nonmetal react, they often form a(an)
kkurt [141]

When two atoms of the same nonmetal react,they form what we know today as a diatomic molecule.

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7 0
3 years ago
Riding a bicycle and using of wheelbarrow (kariton) are example of
ruslelena [56]
Im pretty sure its Rolling friction also know as rolling resistance
4 0
3 years ago
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An object is moving with constant non-zero velocity. Which of thw following statements about it must be true
hram777 [196]

Answer:

The net force on the object is zero.

Explanation:

An object is moving with constant non-zero velocity. If velocity is constant, it means that the change in velocity is equal to 0. As a result, acceleration of the object is equal to 0. Net force is the product of mass and acceleration. Hence, the correct option is (d) "The net force on the object is zero".

5 0
3 years ago
When placed near another charge, a 20 microcoulomb charge experiences an attractive force of 0.080 N. What is the electric field
prohojiy [21]

Answer:

E = 4000 N/C

Explanation:

Given the following data;

Force = 0.080 N.

Charge, q = 20 microcoulomb = 20 * 10^-6 = 2 * 10^-5 Coulombs

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Mathematically, the electric field strength is given by the formula;

Electric field strength = force/charge

Substituting into the formula, we have;

E = 0.080/0.00002

E = 4000 N/C

8 0
3 years ago
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