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Alexxandr [17]
3 years ago
6

What is the midpoints of a segment whose endpoints are (-3, 8) and (7, -2) ?

Mathematics
1 answer:
Sidana [21]3 years ago
3 0
M = (\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})
M = (\frac{7 - (-3)}{2}, \frac{-2 + 8}{2})
M = (\frac{7 - 3}{2}, \frac{6}{2})
M = (\frac{4}{2}, 3)
M = (2, 3)
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Can someone please help me??? And please be sure of ur answer :)
Rina8888 [55]

Answer:

1. is the last one.

2. is the 3rd one.

3. is the first one.

4. is the 2nd one.

Step-by-step explanation:

What you do is you have to get the letter by itself and it all depends on the less than or greater than signs.

For #1. -m+8>6. What you do is you minus 8 from both sides to get -m>-2. You still have a -m so you need to divide both sides by a -1. (<em><u>one thing to remember is when you divide by a negative you have to switch the sign.</u></em>) So your answer will be m<2. That will make the last graph the answer.

For #2. -2p< or equal to -10. What you do is divide by -2. and you need to remember to switch the sign. So your answer is p> or equal to 5.

You will do the same for the other two equations but your answers are.

#1. is the last one graph.

#2. is the 3rd one graph.

#3. is the first one graph.

#4. is the 2nd one graph.

3 0
4 years ago
PLS HELP 30 POINTS PLSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS HELP PLS
svp [43]

Answer:

it's quite difficult

Step-by-step explanation:

I think it will...

5 0
3 years ago
Solve the linear system if 3x+4y-z=-6 5x+8y+2z=2. -x+y+z=0
Anni [7]
We are given with three equations and three unknowns and we need to solve this problem. The solution is shown below:
Three equations are below:
3x + 4y - z = -6
5x + 8y + 2z = 2
-x + y + z = 0

use the first (multiply by +2) and use the second equation:
2 (3x+4y -z = -6)  => 6x + 8y -2z = -12
                               + ( 5x + 8y +2z = 2)
                                  ------------------------
                                     11x + 16y = -10  -> this the fourth equation

use the first and third equation:
 3x + 4y -z = -6
+ (-x + y + z =0)
-------------------------
        2x + 5y = -6 -> this is the fifth equaiton

use fourth (multiply by 2) and use fifth (multiply by -11) equations such as:
2 (11x + 16y = -10)   => 22x + 32y = -20  -> this is the sixth equation
-11 (2x + 5y = -6)    => -22x -55y = 46   -> this is the seventh equation

add 6th and 7th equation such as:
   22x + 32y = -20
+(-22x - 55y = 66)
---------------------------
             - 23y = 46
               <span>   y = -2

solving for x, we have:
</span>2x + 5y = -6 
2x = -6 - 5y
2x = -6 - (5*(-2))
2x = -6 +10
2x = 4
x=2

solving for y value, we have:
-x + y + z =0
z = x -y 
z = 2- (-2)
z =4

The answers are the following:
x = 2
y = -2
z = 4
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4 years ago
If the opposite angle of rhombus are (2x)°and (3x-40°) then what is the value of x?
ch4aika [34]
C I don’t know actually
8 0
3 years ago
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Step2247 [10]
Amanda can buy 20 nectarines with $16
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3 years ago
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