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Alexxandr [17]
3 years ago
6

What is the midpoints of a segment whose endpoints are (-3, 8) and (7, -2) ?

Mathematics
1 answer:
Sidana [21]3 years ago
3 0
M = (\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})
M = (\frac{7 - (-3)}{2}, \frac{-2 + 8}{2})
M = (\frac{7 - 3}{2}, \frac{6}{2})
M = (\frac{4}{2}, 3)
M = (2, 3)
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Step-by-step explanation:

1. Amplitude = 1.  g(x) = 1 sin(6x).  The coefficient 1 is the amplitude.  The range of the function is -1 \le g(x) \le 1  or, in interval notation, [-1, 1]

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3 years ago
6^3=216. Using exponents, write three more expressions whose value is 216.
faltersainse [42]

Answer:

216^1

(2^3)(3^3)

(2*2^2)(3*3^2)

Step-by-step explanation:

To solve this exercise you must keep on mind that according to the exponents rules:

(a^m)(a^n)=a^{(m+n)}

a^1=a

1) Therefore, you can write 216 as:

216^1  

Because: 216^1=216  

2) Descompose the number 216 into its prime factors, then:

216=2*2*2*3*3*3=(2^3)(3^3)

Then you can write the number 216 as (2^3)(3^3)

3) You can also write 216 as following:

(2*2^2)(3*3^2)

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