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Elanso [62]
4 years ago
15

A dog allergy test for people a 98% accuracy rate.Only 1% of the population has an allergy to dogs(actually it is much smaller t

han that!). Use a group of 100,000 people who’ve taken this test and the information provided to complete a table and answer the following question:
If you tested negative,what is the probability you do not have a dog allergy?
(Express your answer as decimals rounded to four decimal places.)
Mathematics
1 answer:
algol [13]4 years ago
6 0

Answer:

It is 0.9990

As is 0.0010 as four decimal places. for those that do have which means the same as a negative probability that you don't but reaffirms the situation so inverse of 0.0010 is needed to be 0.9990. so when added together they can become 100% = 1 whole as a probability that both options equal together 1.

When questions ask it negatively using words like don't, haven't, didn't etc. etc.

This question asks for such probability which is similar to percentage in scale for those that do have an allergy.

If the question asked the probability you do have a non allergy the opposite effect happens and we inverse the answer to 99%

But because it asks negatively that you dont have we keep the establishing number of the actual allergy finding because its the same as if you don't.

1% of 100,000 = 1000

1000/100000 = 1/1000

1/1000 = 0.001

Step-by-step explanation:

Once you find 1/1000 is answer to turn numbers into decimals remember the rule 1 = 100

So if 1 = 100

and we want 1/100

1/100 will equal and simplify into 0.01

Where 1/1000 will equal and simplify into 0.001 as the number 100 is extended another digit so would the decimal.

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The amount of time people spend exercising in a given week follows a normal distribution with a mean of 3.8 hours per week and a
Travka [436]

Answer:

i and iii) In the figure attached part a we have the illustration for the area required for the probability of less than 2 hours and in b the illustration for the probability that X would be between 2 and 4

ii) P(X

And using the normal standard table or excel we got:

P(z

iv) P(2

And we can find the probability with the following difference and usint the normal standard distirbution or excel and we got:

P(-2.25

Step-by-step explanation:

Let X the random variable that represent amount of time people spend exercising in a given week, and for this case we know the distribution for X is given by:

X \sim N(3.8,0.8)  

Where \mu=3.8 and \sigma=0.8

Part i and iii

In the figure attached part a we have the illustration for the area required for the probability of less than 2 hours and in b the illustration for the probability that X would be between 2 and 4

Part ii

We are interested on this probability:

P(X

We can use the z score formula given by:

z=\frac{x-\mu}{\sigma}

Using this formula we have:

P(X

And using the normal standard table or excel we got:

P(z

Part iv

We want this probability:

P(2

Using the z score formula we got:

P(2

And we can find the probability with the following difference and usint the normal standard distirbution or excel and we got:

P(-2.25

3 0
4 years ago
You can fly from Seattle to Boise for $137.50, from Boise to Witchita for $92.50 and from Witchita to Austin for $162.50. Use me
jonny [76]
That would be  392.50  

6 0
3 years ago
Read 2 more answers
Make sure you draw a picture to help solve the problem and show all your work:
hodyreva [135]

Answer:

answer in the pic

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below ;)

3 0
3 years ago
True or False? If x>0 and a>1, then (ln x/ln a) = ln (x/a) Counter example if false.
valentinak56 [21]
<span>It's False!
If a=e and x=1, you'll get: </span>ln(1)ln(e)=01=0 \neq -1=(−1)ln(e)=ln( e^{-1})=ln(\frac{1}{e}  )
3 0
3 years ago
Hey guys can you please help me?? Thank you!
yarga [219]
The answer is 5 :)
44+51=95
180-95=85
85/17=5
answer: 5
3 0
3 years ago
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