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4 years ago

8

PLEASE HELP!!! Match each equation with its slope

1 answer:

GrogVix [38]4 years ago

8 0

Y=2 has a slope of M=0
y=x has a slope of M=1
x=6 has an undefined slope
y-3x=7 has a slope of M=3
y=-3x+2 has a slope of M=-3
x+y=1 has a slope of M=-1

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If 2x-4(3-x)=18, then x=_____? Can someone please help me with this problem

denis-greek [22]

Answer:

Answer is below

Step-by-step explanation:

Simplify both sides of the equation.

$2x-4(3-x)=18\\2x+(-4)(3)+(-4)(-x)=18$

DIstribute

$2x+-12+4x=18\\(2x+4x)+(-12)=18$

CLT

$6x+-12=18\\6x-12=18$

Add 12 to both sides.

$6x-12+12=18+12\\6x=30$

Divide both sides by 6.

$\frac{6x}{6} =\frac{30}{6}\\ x=5$

7 0

3 years ago

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

4 years ago

As an estimation we are told £3 is €4.

hram777 [196]

Answer:

From the estimation,

£10.7 = €14.27

Step-by-step explanation:

Given the conversion rate between the pounds and the euro currencies, we are to convert an amount in pounds to euros

From the estimate;

3 pounds = 4 euros

Thus;

10.7 pounds = x euros

We are using x since the value in euros is not known presently.

To move from here, we simply cross multiply.

That would give;

3 * x = 4 * 10.7

3x = 42.8

x = 42.8/3

x = 14.2666

x = €14.27

4 0

3 years ago

Algebra Help please?

tresset_1 [31]

According to the table, $f(x)=g(x)$ when $x=0$ because $f(0)=g(0)=1$ , and when $x=1$ because $f(1)=g(1)=0.25$ .

4 0

4 years ago

Transform the equation to isolate x:ax=bx + 1 how is the value of x related to the difference of a and b

Airida [17]

Answer:

x = $\frac{1}{a-b}$

Step-by-step explanation:

Given

ax = bx + 1

Collect the terms in x on the left side by subtracting bx from both sides

ax - bx = 1 ← factor out x from each term on the left side

x(a - b) = 1 ← divide both sides by (a - b)

x = $\frac{1}{a-b}$

4 0

3 years ago

Read 2 more answers