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3 years ago

What would cause the percent yield of a reaction to be less than 100%?

Chemistry

1 answer:

AysviL [449]3 years ago

7 0

<h3>Answer:</h3>

The product participates in a side reaction.

<h3>Explanation:</h3>

Many are times that chemical reactions do not yield a 100% of the product required.

This is attributed to a number of factors which include;

Presence of impurities
Side reactions by reactants or products
Reactions not attaining completion.
Errors during the experiment.

Percentage yield is calculated by diving the actual or experimental yield by theoretical yield and multiplying by 100.

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Determine the value of the equilibrium constant, Kgoal, for the reaction

hodyreva [135]

Answer:

Part A

$K_{goal}= 3.22\times 10 ^{-66}$

Part B

$K_{goal}= 2.26\times10^{-21}$

Explanation:

Part A:

The given equation is not balanced. So, initially let's balance the equation by taking 24 moles of each of the reagent and NO.

24N₂ + 24H₂O ⇌ 24NO + 12N₂H₄

Now, simplify the equation by dividing both sides by 12. The final balanced equation is the following

2N₂ + 2H₂O ⇌ 2NO + N₂H₄

The above-balanced equation can be solved algebraically to obtain the required Kgoal value.

Adding given equations 1, 2 and 3 we obtain the required equation.

When the equations are added, the equilibrium constants of each equation are multiplied. Mathematically it can be represented as,

$K_1 \times K_2 \times K_3 = K_{goal}$

$K_{goal}= 4.10 \times 10^{-31} \times 7.40 \times 10^{-26} \times 1.06 \times 10^{-10}$

$K_{goal}= 3.22\times 10 ^{-66}$

Part B:

The required equation is balanced, Now

Let.

P₄(s)+6Cl₂(g) ⇌ 4PCl₃(g), K₁=2.00×10¹⁹ ------------------------------------ (a)

PCl₅(g) ⇌ PCl₃(g)+Cl₂(g), K₂=1.13×10⁻² --------------------------------------- (b)

By multiplying equation 2 by 4 and subtracting equation 1 from it, we get

4PCl₅(g) ⇌ P₄(s)+10Cl₂(g)

The Kgoal for the above equation is the product of four times K₂ and inverse K₁ according to the applied operation. Mathematically,

$K_{goal}= 4K_2 \times \frac{1}{K_1}$

$K_{goal}= 4(1.13\times10^{-2}) \times \frac{1}{2.00\times10^{19}}$

$K_{goal}= 2.26\times10^{-21}$

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rewona [7]

I believe the correct answer to this question is:

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<span>This is as opposed to Compounds which are chemically bonded and cannot be separated by physical means.</span>

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4 years ago

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