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defon
3 years ago
5

Explanation of electron configuration

Chemistry
1 answer:
MrRissso [65]3 years ago
6 0

Answer:

the electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals

Explanation:

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A chemist wishing to do an experiment requiring 47Ca2+(half-life = 4.536 days) needs 5.00 g of the nuclide. What mass of 47CaCO
Artyom0805 [142]

Answer: The answer is 6.78 grams.

Explanation: The equation used for solving this type of problems  is:

\frac{N}{N_0}=(\frac{1}{2})^n

where, N_0 is the initial amount of radioactive substance, N is the remaining amount and n is the number of half lives.

Number of half lives is calculated on dividing the given time by the half life.

n = time/half life

Time is given as 48.0 hours and the half life is given as 4.536 days. let's make the units same and for this let's convert the half life from days to hours.

4.536days(\frac{24hours}{1day})

= 108.864 hours

So, n=\frac{48.0}{108.864}  = 0.441

Since 5.00 g is the required amount when the radioactive substance is delivered to the scientist, it would be the final amount that is N. We need to calculate the initial amount. Let's plug in the values in the equation:

\frac{5.00}{N_0}=(\frac{1}{2})^0^.^4^4^1

\frac{5.00g}{N_0}=0.737

N_0=\frac{5.00g}{0.737}

N_0 = 6.78 g

So, 6.78 g of the radioactive substance needs to be ordered.

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How to make caramel from condensed milk on the stove?.
laila [671]

Answer:

Bring to the boil. Carefully place the can in the saucepan, ensuring there's enough water to completely cover the can at all times, topping up water frequently throughout the cooking process. Simmer, uncovered for 3 hours.

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What is the mass (in grams) of 5.00 L of NH₃ at STP?
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Explanation:

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