Answer:
A team of Chinese researchers have turned cheap copper into a new material “almost identical” to gold, according to a study published in peer-reviewed journal Science Advances on Saturday. The fast-moving ionized particles blasted copper atoms off the target.
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Explanation:
Answer:
![\% O=27.6\%](https://tex.z-dn.net/?f=%5C%25%20O%3D27.6%5C%25)
Explanation:
Hello,
In this case, for the sample of the given compound, we can compute the moles of each atom (carbon, hydrogen and oxygen) that is present in the sample as shown below:
- Moles of carbon are contained in the 9.582 grams of carbon dioxide:
![n_C=9.582gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2} =0.218molC](https://tex.z-dn.net/?f=n_C%3D9.582gCO_2%2A%5Cfrac%7B1molCO_2%7D%7B44gCO_2%7D%2A%5Cfrac%7B1molC%7D%7B1molCO_2%7D%20%20%3D0.218molC)
- Moles of hydrogen are contained in the 3.922 grams of water:
![n_H=3.922gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} =0.436molH](https://tex.z-dn.net/?f=n_H%3D3.922gH_2O%2A%5Cfrac%7B1molH_2O%7D%7B18gH_2O%7D%20%2A%5Cfrac%7B2molH%7D%7B1molH_2O%7D%20%3D0.436molH)
- Mass of oxygen is computed by subtracting both the mass of carbon and hydrogen in carbon dioxide and water respectively from the initial sample:
![m_O=4.215g-0.218molC*\frac{12gC}{1molC} -0.436molH*\frac{1gH}{1molH} =1.163gO](https://tex.z-dn.net/?f=m_O%3D4.215g-0.218molC%2A%5Cfrac%7B12gC%7D%7B1molC%7D%20-0.436molH%2A%5Cfrac%7B1gH%7D%7B1molH%7D%20%3D1.163gO)
Finally, we compute the percent by mass of oxygen:
![\% O=\frac{1.163g}{4.215g}*100\% \\\\\% O=27.6\%](https://tex.z-dn.net/?f=%5C%25%20O%3D%5Cfrac%7B1.163g%7D%7B4.215g%7D%2A100%5C%25%20%5C%5C%5C%5C%5C%25%20O%3D27.6%5C%25)
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Answer:
2.74 x 1023 molecules of CO2.
Explanation:
There are 2.74 x 1023 molecules of CO2.
The correct answer is the second option. During fusion, uranium atoms are fused together. Fusion reaction happens when two or more nuclei combine or collide to form an element with a higher atomic number. In this process, some of the matter of the fusing nuclei is converted to energy.