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defon
4 years ago
8

Which triangle is ​△ABC​ similar to and why?

Mathematics
1 answer:
Rudik [331]4 years ago
8 0
<span>△ABC is similar to △JKL by ​ AA Similarity Postulate.

Explication:

For </span>ΔABC 
<span>
m</span>∠A + m∠B + m∠C = 180°
  20° +   80° + m∠C = 180°
      100° + m∠C = 180°
<span>            m</span>∠C = 80°<span>

Two angle pairs are congurent </span>⇒ △ABC ~ <span>△JKL</span>
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The equation is 36 - 4x = 6.

Solution:

To write the equation without fraction.

$4-\frac{4}{9} x=\frac{2}{3}

$\frac{4}{1} -\frac{4}{9} x=\frac{2}{3}

The denominators must be same to add/subtract the fractions.

LCM of 1, 9 and 3 = 9.

Multiply first term by \frac{9}{9} and \frac{2}{3} by \frac{3}{3} to make the denominator same.

$\frac{4\times9}{1\times9} -\frac{4}{9} x=\frac{2\times3}{3\times3}

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$\frac{36-4x}{9} =\frac{6}{9}

Multiply by 9 on both sides.

$\frac{36-4x}{9}\times9 =\frac{6}{9}\times9

Both 9 in the numerator and denominator get canceled.

36 - 4x = 6

This term does not have fraction.

Hence the equation is 36 - 4x = 6.

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Answer:

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Step-by-step explanation:

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2(ab^3 - 7ab +8a)

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