Which triangle is △ABC similar to and why?
1 answer:
<span>△ABC is similar to △JKL by AA Similarity Postulate.
Explication:
For </span>ΔABC
<span>
m</span>∠A + m∠B + m∠C = 180°
20° + 80° + m∠C = 180°
100° + m∠C = 180°
<span> m</span>∠C = 80°<span>
Two angle pairs are congurent </span>⇒ △ABC ~ <span>△JKL</span>
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