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3 years ago

Question 5

Engineering

2 answers:

likoan [24]3 years ago

8 0

Answer:

worth of being noticed

Explanation:

i had this in iready it’s correct trust me

MAVERICK [17]3 years ago

5 0

Answer:

worthy of being noticed

Explanation:

i know because i got it right on the i-ready quiz

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Write a SELECT statement that returns the same result set as this SELECT statement. Substitute a subquery in a WHERE clause for

sergiy2304 [10]

Answer:

SELECT distinct VendorName FROM Vendors

WHERE VendorID IN (

SELECT VendorID FROM Invoices

)

Explanation:

6 0

3 years ago

When its 100-hp engine is generating full power, a small airplane with mass 700 kggains altitude at a rate of 2.5 m/s. What frac

snow_lady [41]

For the given problem it is necessary to recap the concepts about Power, that is, is the rate of doing work or of transferring heat, i.e. the amount of energy transferred or converted per unit time.

The equation for power can be written as

$P = FV$

Where,

F= Net Force

V =Velocity

By the second newton law, force can be:

F = mg

Where m means the mass and g the gravity acceleration.

We can also write the equation as,

P = mgv

Replacing the values

P = 700*9.8*25

P = 17.15kW

Tenemos unidades en dos sistemas diferentes, por lo que convertimos los HP a Sistema internacional y tenemos que

1hp = 0.746kW

Then the fraction $\eta$ is,

$\eta = \frac{17.15kW}{0.746kW}$

$\eta = 22.989$

Therefore the fraction of the engine power is being used to make the airplane climb is 22.984%

5 0

3 years ago

A completely reversible heat pump produces heat ata rate of 300 kW to warm a house maintained at 24°C. Theexterior air, which is

Triss [41]

Answer:

Change in entropy S = 0.061

Second law of thermodynamics is satisfied since there is an increase in entropy

Explanation:

Heat Q = 300 kW

T2 = 24°C = 297 K

T1 = 7°C = 280 K

Change in entropy =

S = Q(1/T1 - 1/T2)

= 300(1/280 - 1/297) = 0.061

There is a positive increase in entropy so the second law is satisfied.

6 0

3 years ago

A vehicle of 1 200 kg is moving at a speed of 40 km/h on an incline of 1 in 50. The total constant rolling and wind resistance i

Readme [11.4K]

Answer:11.602 KW

Explanation:

mass of vehicle $\left ( m\right )=1200 kg$

speed=40Km/h

Resistance=600 N

$\eta =80%$

Gear ratio $\left ( G\right )=4:1$

$D_{effective}=500mm$

Net force to overcome by engine is

F=Resistance + sin component of weight

F=600+ $mgsin\theta$

Where $tan\theta =[tex]\frac{1}{50}$

$\theta =1.1457^{\circ}$

$F=600+1200\times 9.81\times sin\left ( 1.1457\right )$

F=600+235.38=835.38 N

power= $F.v=835.38\frac{100}{9}$

Engine Power= $\frac{835.\frac{100}{9}}{\eta }$ =11.602 KW

4 0

4 years ago

Technician A says some coolant recovery systems are pressurized. Technician B says the coolant recovery system is used to keep a

Digiron [165]

Answer: Technician A

Explanation: A coolant recovery system Is one of the most important part of a vehicles cooling system. When a coolant gets too hot, it forces it way out of the spring loaded radiator cap so as to relieve pressure. Any coolant which has escaped is recovered back through the discharge tube located in the recovery tank. The system is usually air free

8 0

3 years ago