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Anestetic [448]
3 years ago
11

An existing building is suffering from cracks in the exterior walls. The investigating engineer wants to ensure that the foundat

ions are not overloaded. The existing columns carry dead live load of 45,000 pounds. The footings are 3 ft 6 in. x 3 ft 6 in. x 1 ft 6 in. thick and rest on sandy soil. The soils report estimates the allowable soil bearing pressure to be 2500 psf. What would be the smallest area for a safe footings are adequate to carry the load?
Engineering
1 answer:
jek_recluse [69]3 years ago
6 0

Answer:

18 ft^{2}

Explanation:

Soil bearing pressure=\frac {Load}{Area}

Since we're given pressure of 2500 psf and load of 45000 pounds

The area=\frac {45000}{2500}=18

Therefore, the smallest area of safe footings should not be less than 18 ft^{2}

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Technician A says that 18 gauge AWG wire can carry more current flow that 12 gauge AWG wire. Technician B says that metric wire
denpristay [2]

Answer:

Technician B

Explanation:

Both AWG and metric are sized by cross-sectional area.

Technician A is wrong:  12 gauge wire is larger diameter rated for 20 amps in free air.  18 awg is smaller diameter and typically used for speaker wiring, Class II or low voltage and sub-circuits within appliances.

6 0
3 years ago
A flame ionization detector, which is often used in gas chromatography, responds to a change in
Lena [83]

Answer:

Option A

Explanation:

We know that ions are present in hydrogen-air flame and when the burning of an organic compound takes place in this flame more ions are produced in the flame.  

Thus when we apply a voltage across this flame, the ion collector plate attracts the all the ions in the flame.

The presence of organic compounds increases the voltage across the hydrogen ion flame produced at the ion collector increases and as the voltage increases, the detection of the organic compound can be made in turn.

Thus flame ionization detector clearly responds to the variation in the collection of ions or electrons in a flame.

3 0
3 years ago
1. A thin plate of a ceramic material with E = 225 GPa is loaded in tension, developing a stress of 450 MPa. Is the specimen lik
mina [271]

Answer:

fracture will occur as the value is less than E/10 (= 22.5)

Explanation:

If the maximum strength at tip Is greater than theoretical fracture strength value then fracture will occur and if the maximum strength is lower than theoretical fracture strength then no fracture will occur.

\sigma_m = 2\sigma_o [\frac{a}{\rho_t}]^{1/2}

=  2\times 750 (\frac{\frac{0.2mm}{2}}{0.001 mm}})^{1/2}

                 = 15 GPa

fracture will occur as the value is less than E/10 = 22.5

7 0
3 years ago
Write the implementation (.cpp file) of the Player class from the previous exercise. Again, the class contains:
hoa [83]

Answer:

//Define the header file

#ifndef PLAYER_H

#define PLAYER_H

//header file.

#include <string>

//Use the standard namespace.

using namespace std;

//Define the class Player.

class Player

{

//Declare the required data members.

string name;

int score;

public:

//Declare the required

//member functions.

void setName(string par_name);

void setScore(int par_score);

string getName();

int getScore();    

}

//End the definition

//of the header file.

#endif

Player.cpp:

//Include the "Player.h" header file,

#include "Player.h"

//Define the setName() function.

void Player::setName(string par_name)

{

name = par_name;

}

//Define the setScore() function.

void Player::setScore(int par_score)

{

score = par_score;

}

//Define the getName() function.

string Player::getName()

{

return name;

}

//Define the getScore() function.

int Player::getScore()

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return score;

}

7 0
3 years ago
NO LINK plsssss just answer
solmaris [256]

Answer:

Explanation:

4 0
2 years ago
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