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schepotkina [342]

4 years ago

7

The water in a 150 ml flask is poured into a beaker that contain 600 ml of ethyl aclchol which of the substance is solvent in th

is mixture

2 answers:

Mariana [72]4 years ago

8 0

Answer:

C. ethyl alcohol because it has a much larger volume than water

aev [14]4 years ago

5 0

The ethyl alcohol that's wat it is

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A sample of lemon juice has a pH of 3. What is the [OH-] concentration of the lemon juice? A) 11 B) 1 X 10+3 C) 1 X 10-3 D) 1 X

Likurg_2 [28]

pH scale is used to determine the acidity of a solution

pH is calculated using the H⁺ concentration

pOH scale is used to determine how basic a solution is

pOH is calculated using the OH⁻ concentration

pH and pOH are related in the following formula

pH + pOH = 14

pH = 3

pOH = 14 - 3

pOH = 11

pOH is calculated using the following formula

pOH = - log[OH⁻]

[OH⁻] = antilog(-pOH)

[OH⁻] = antilog(-11)

[OH⁻] = 1 x 10⁻¹¹ M

the [OH⁻] concentration of lemon juince is D) 1 x 10⁻¹¹ M

5 0

3 years ago

Read 2 more answers

Calculate the ratio of the mass ratio of SS to OO in SOSO to the mass ratio of SS to OO in SO2SO2. Consider a sample of SOSO in

Veronika [31]

Answer:

The ratio of the mass ratio of S to O; in SO, to the mass ratio of S to O; in SO₂, is 2:1

Explanation:

According to the consideration, let us first find the ratio of S and O in both the compounds

For SO:

$\frac{m_{S} }{m_{O} }= \frac{32}{16}\\\\ \frac{m_{S} }{m_{O} }= 2$

Let us express it as

$SO_{\frac{m_{S} }{m_{O} }} = 2$

For SO₂,

Due to two oxygen atoms in the molecule, the mass of oxygen will be taken two times

$\frac{m_{S} }{m_{O} }= \frac{32}{(2)(16)}\\\\ \frac{m_{S} }{m_{O} }= 1$

Let us express it as

$SO_2_{\frac{m_{S} }{m_{O} }}= 1$

Now, for the ratio of both the above-calculated ratios,

$\frac{SO_{\frac{m_{S} }{m_{O} }}}{SO_2_{\frac{m_{S} }{m_{O} }}}=\frac{2}{1}$

The required ratio is 2:1

3 0

3 years ago

C is the element symbol for which element?<br>a. Carbon<br>b. Cadmium<br>c. Celenium<br>d. Chlorine

il63 [147K]

Answer:

A) Carbon

Explanation:

the others are wrong its A

6 0

3 years ago

Read 2 more answers

A scientist observed a 5-mL sample of an unknown substance. It is a blue liquid with a density of 1.2 g/cm. the substance reacts

LenaWriter [7]

Characteristic properties can be used to describe and identify the substances, while non-characteristic properties, although can be used to describe the substances, cannot be used to identify them.

Temperature, mass, color, shape and volume are examples of non-characteristic properties.

Density, boiling point, melting point, chemical reactivity are examples of characteristic properties.

List of the properties observed by the scientist:
-----------------------------------------------------------------
Property                                     Type of property
----------------------------------------------------------------
Volume: 5 ml                              non-characteristic
----------------------------------------------------------------
Color: blue                                 non-characteristic
----------------------------------------------------------------
State: liquid                                characteristic
------------------------------------------------------------
density: 1.2 g/cm                        characteristic
------------------------------------------------------------
Reaction: reacts with CO2         characteristic
----------------------------------------------------------

5 0

3 years ago

500 mL solution of calcium chloride with a concentration of 0.75 mol/L. The mass of solute needed to make this solution is ___ _

BabaBlast [244]

Answer:

41.63g

Explanation:

Given parameters:

Volume of CaCl₂ = 500mL = 0.5L

Concentration = 0.75mol/L

Unknown:

Mass of the solute needed = ?

Solution:

The mass of the solute can be derived using the expression below;

Mass = number of moles x molar mass

But,

Number of moles = Concentration x Volume

So;

Mass = Concentration x Volume x molar mas

Molar mass of CaCl₂ = 40 + 2(35.5) = 111g/mol

Mass = 0.75 x 0.5 x 111 = 41.63g

5 0

3 years ago